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2 years ago

What is the surface area of the regular pyramid given below?

Mathematics

1 answer:

frosja888 [35]2 years ago

3 0

Answer:

Total Surface Area of the given regular pyramid = 153 units²

Step-by-step explanation:

Base length of the regular pyramid, l = 9 units

Base width of the regular pyramid, w = 9 units

Height of the regular pyramid, h = 7 units

Perimeter of base = 3 × 9

= 27 units

$\text{Area of base = }\frac{1}{\times Base\times Height\\\\Area = \frac{1}{2}\times 9\times 7=21.5\:\:units^2$

$\text{Now, Total Surface Area = }\frac{1}{2}\times p\times l+A\\\\\implies\text{Total Surface Area = }\frac{1}{2}\times 27\times 9+31.5$

Hence, Total Surface Area of the given regular pyramid = 153 units²

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dimaraw [331]

Answer:

2,000

Step-by-step explanation:

The computation of the price that should be sold for making 25% profit is shown below:

Let cost price be x

Now the equation would be

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1,920 - x = x - 1,280

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Now the sale price would be

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2 years ago

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(4x2 + 2y)(3x+y^2)

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3 years ago

Read 2 more answers

Please help me with my hw

stellarik [79]

Part 2 is 12.5 cm represents 5km
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2 years ago

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Evgesh-ka [11]

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3 years ago

Find the function value. tan495°

inysia [295]

Answer: -1

Step-by-step explanation:

You want to find an angle that is coterminal to 495. So, subtract 360 degrees until youre in the range of 0-360. I got 495 - 360 = 135°

Tangent is equal to $\frac{sin(theta)}{cos(theta)}$ , we already solved theta which was 135°

This next part is hard to explain to someone who doesnt know their trig circle, idk if you do. The angle 135 is apart of the pi/4 gang. So we know this is going to be some variant of √2/2. Sine of quadrant 1 and 2 is gonna be positive:

$sin135=\frac{\sqrt{2} }{2}$

Now lets do cosine of 135°, which again is apart of the pi/4 gang because its divisible by 45°. Its in quadrant 2 so the cosine will be negative.

$cos135=-\frac{\sqrt{2} }{2}$

The final step is to divide them. They are both fractions so you should multiply by the reciprocal.

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3 years ago

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