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BaLLatris [955]
3 years ago
14

Can someone help me with 9,10,11 ?

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
3 0
I could be wrong but i graphed it out and 9 is C , 10 is A , and 11 is C Hopefully it's right
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Write the linear inequality shown in the graph.
Korolek [52]
Fist, in the equation y=mx+b, b is the y-intercept. The y-intercept is the poin on the line that crosses the x-axis; the y-intercept is the value of yThese equations follow that format. 
Y=mx+b
y\geq 3x-4. <-----In this equation, the slope(m)=3 b= -4. 

On the graph, we can see that the line crosses the x-axis at y=-4. Knowing that, we can eliminate the answer choices with +4 in the inequality.


The next step, is to pick an (x,y) coordinate that is in the shaded region and plug it into the remaining 2 inequalities. Which ever inequality is true after you solve it, that is the correct answer.  
For example, I'll choose to plug in (-4,4) into the y\geq 3x-4. 
y\geq 3x-4. 
(4)\geq (3(-4))-4. 
(4)\geq (-12)-4. 
(4)\geq -16

So, this statement is true becasue -16 is less than positive 4.  Therefore, the correct answer would be y\geq 3x-4. Hope that helped! Comment back with any further questions!


6 0
3 years ago
More math sorry. But I honestly don’t know any of these
DIA [1.3K]

Answer: A

Step-by-step explanation:

The main parent functions are x, and x raised to the power of something (examples: x^2, x^3, x^4, etc)

8 0
3 years ago
Solve for b.<br> 35b=14<br> Simplify your answer as much as possible.
ELEN [110]

Answer:

b=2/5

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Identify the roots of the function g(x) = x^2 - 8x + 16
amm1812
Only 4 because result is (x-4)(x-4) that means (x-4)^2=0
So
X-4=0
X=4
8 0
3 years ago
Can someone please just tell me how to answer any question like this PLEASE!
rjkz [21]

Answer:after multiplying , u then count the number of decimal places in the question and fix it in the answer,it should be from the right  to the left  

Step-by-step explanation:

43644+65466=698304

Then=6.98304

5 0
2 years ago
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