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2 years ago

Pls help!

Mathematics

1 answer:

Marina86 [1]2 years ago

5 0

The way to solve this is to try to get the vales that would best fill the empty spaces in the diagram. This has been done below

a. log6⁰, log 2 . 1, log 8/3

b. log 1 .4 , 1 , log 4. 6

c. log 9/2, log 3. 5 , log 5⁷

<h3>How to find the logarithm of a number</h3>

To do this, you have to decide on that specific number whose logarithm you are trying to determine. Next you have to find the base of that number.

The logarithm of the number is the power that it would have to be raised for us to obtain a different number.

Read more on the logarithm of a number here: brainly.com/question/1807994

#SPJ1

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What is the base 10 representation of the number 1046(8)

Hitman42 [59]

1046₈ = 1*8³ + 0*8² + 4*8¹ + 6*8⁰

1046₈ = 512 + 0 + 32 + 6

1046₈ = 550₁₀

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4 years ago

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Does anyone know the answer ? :(

weeeeeb [17]

Answer:

If it a khan you can go take a hint and try to find it

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3 years ago

What is the y-value of the vertex of the function f(x)=-(x-3)(x+11)

lutik1710 [3]

so, this is a quadratic equation, meaning two solutions, and we have a factored form of it, meaning you can get the solutions by simply zeroing out the f(x).

$\bf \stackrel{f(x)}{0}=-(x-3)(x+11)\implies 0=(x-3)(x+11)\implies x= \begin{cases} 3\\ -11 \end{cases} \\\\\\ \boxed{-11}\stackrel{\textit{\large 7 units}}{\rule[0.35em]{10em}{0.25pt}}-4\stackrel{\textit{\large 7 units}}{\rule[0.35em]{10em}{0.25pt}}\boxed{3}$

so the zeros/solutions are at x = 3 and x = -11, now, bearing in mind the vertex will be half-way between those two, checking the number line, that midpoint will be at x = -4, so the vertex is right there, well, what's f(x) when x = -4?

$\bf f(-4)=-(-4-3)(-4+11)\implies f(-4)=7(7)\implies f(-4)=49 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{vertex}{(-4~~,~~49)}~\hfill$

7 0

3 years ago

How to solve this problem by finding x

LekaFEV [45]

Answer:

X=140

Step-by-step explanation:

<em>Firstly, any Quadrilateral has a total sum of its angle equal to 360 degrees</em>

<em>The attachment you are showing us shows that we already know two angles</em>

<em>(70)&(60) degrees. I am assuming the line DC is a tangent, so angle ADC must be 90 degrees since a full angle on a tangent is equal to 180 degrees and there is 90 from the other side (180-90=90). Now we know 3 angles and what you have to do is find X so that when you add them all up they make a sum of 360. </em>

<em />

X+70+60+90=360

X=360-70-60-90

X=140

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3 years ago

Read 2 more answers

A library subscribes to two different weekly news magazines, each of which is supposed to arrive in Wednesday's mail. In actuali

Dominik [7]

Answer:

y 0 1 2 3

P(Y=y) 0.0676 0.3549 0.3875 0.19

Step-by-step explanation:

P(Wed) = 0.26

P(Thurs) = 0.39

P(Fri) = 0.25

P(Sat) = 0.10

Y = No. of days beyond Wednesday it takes for both magazines to arrive i.e. 0,1,2,3

Y=0 means the magazines will arrive on Wednesday

Y=1 means the magazines will arrive till Thursday

Y=2 means the magazines will arrive till Friday

Y=3 means the magazines will arrive till Saturday

The possible combinations for Y are

Y(W,W) Y(W,T) Y(W,F) Y(W,S)

Y(T,W) Y(T,T) Y(T,F) Y(T,S)

Y(F,W) Y(F,T) Y(F,F) Y(F,S)

Y(S,W) Y(S,T) Y(S,F) Y(S,S)

So, we can classify these possible outcomes as Y=0,1,2,3.

Y(0) = Y(W,W) (both magazines take 0 days to arrive beyond Wednesday)

Y(1) = Y(W,T), Y(T,T), Y(T,W) (both magazines take 1 day to arrive beyond Wednesday)

Y(2) = Y(W,F), Y(T,F), Y(F,F) Y(F,W) Y(F,T) (both magazines arrive till Friday)

Y(3) = Y(W,S), Y(T,S), Y(F,S), Y(S,W), Y(S,T), Y(S,F), Y(S,S) (both magazines arrive till Saturday)

To calculate the PMF, we need to calculate the probability for each of the points in Y(0,1,2,3).

Y(0) = Y(W,W)

= 0.26 x 0.26

Y(0) = 0.0676

Y(1) = Y(W,T) + Y(T,T) + Y(T,W)

= (0.26 x 0.39) + (0.39 x 0.39) + (0.39 x 0.26)

= 0.1014 + 0.1521 + 0.1014

Y(1) = 0.3549

Y(2) = Y(W,F) + Y(T,F) + Y(F,F) + Y(F,W) + Y(F,T)

=(0.26 x 0.25) + (0.39 x 0.25) + (0.25 x 0.25) + (0.25 x 0.26) + (0.25 x 0.39)

= 0.065 + 0.0975 + 0.0625 + 0.065 + 0.0975

Y(2) = 0.3875

Y(3) = Y(W,S) + Y(T,S) + Y(F,S) + Y(S,W) + Y(S,T) + Y(S,F) + Y(S,S)

= (0.26 x 0.10) + (0.39 x 0.10) + (0.25 x 0.10) + (0.10 x 0.26) + (0.10 x 0.39) + (0.10 x 0.25) + (0.10 x 0.10)

= 0.026 + 0.039 + 0.025 + 0.026 + 0.039 + 0.025 + 0.010

Y(3) = 0.19

y 0 1 2 3

P(Y=y) 0.0676 0.3549 0.3875 0.19

The PMF plot is attached as a photo here.

7 0

4 years ago