This is a sinusoidal wave with an <u>amplitude of 2</u> , riding on a constant value of 3 .
The 3 isn't part of the function's amplitude ... the function wiggles between 2 under it
and 2 over it.
The period of the function is the change in 'x' that adds (2 pi) to the angle.
When x=0, the angle is pi
When the angle is (3 pi) . . .
3 pi = 3x + pi
2 pi = 3x
x = 2/3 pi <u>The period of the function is 2/3 pi </u>.
When x=0, the function is cos(pi) rather than cos(0).
So the function is a cosine with a <u>phase shift of +pi</u>.
It could also be described as a sine with a phase shift of -pi/2 or +3pi/2 .
You would graph the two lines. Then use Y=mX+b
10=5/4(4)+b 5/4 is the slope or distance between the two lines.
solve for b
10=5+b
-5
5=b
Y=5/4X+5 would be your answer
Answer:
x-5=3x+1 (x=-3)
Step-by-step explanation:
5 less (_-5)
than a number (x)
is equivalent to (=)
1 more than (+1)
than three times the number (3x)
combine them all to get x-5=3x+1
extra:
add 5 to each side x=3x+6
subtract x from each side 0=2x+6
subtract 6 from each side -6=2x
divide each side by 2 -3=x
You do 244 divide by sixty and your answer is 4.06
Answer:
There is no question I am confused
Step-by-step explanation:
