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Triss [41]
3 years ago
10

I don’t know how to solve number 8?

Mathematics
2 answers:
sveticcg [70]3 years ago
8 0
When you combine 6 and 4 and reorder the terms, it's 2c^2 - 5c + 10
Mila [183]3 years ago
8 0
All you have to do is combine the ones you circled (6 and 4). You leave the ones woth variables alone because one is squared while the other isn't. You're answer should be: 2c^2 - 5c + 10
Hoped this helped!
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When two numbers are not equal, an a0 is a sentence that uses the symbols >, <, ≥, ≤, or ≠ to show a relationship.
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Answer: Im pretty sure it is the equal sign with the line between it

pretty sure that is it tho

Hope that helped

Step-by-step explanation:

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Can you help me with this word problem?​
dangina [55]

Answer:

The ratio of flour to sugar is 2:1

Step-by-step explanation:

Let f = weight of a bag of flour

Let s = weight of a bag of sugar

3f+2s = 32

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4f=32

Divide by 4

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artcher [175]
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3 years ago
Given that f(x) = x + 3<br> a) Find f(2)
Nataly_w [17]

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

In the above question, it is given that :

\qquad \sf  \boxed{ \sf f(x) =  \frac{x + 3}{2} }

A.) Find f(2) :

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{2 + 3}{2}

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{5}{2}

or

\qquad \sf  \dashrightarrow \: f(2) = 0.5

B.) Find { \sf {f}^{-1}(x) } :

\qquad \sf  \dashrightarrow \: let \: y = f (x)

so, we can write it as :

\qquad \sf  \dashrightarrow \: y =  \dfrac{x + 3}{2}

\qquad \sf  \dashrightarrow \: 2y = x + 3

\qquad \sf  \dashrightarrow \: x = 2y - 3

Now, put x = { \sf {f}^{-1}(x) }, and y = x and we will get our required inverse function ~

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3

C.) Find { \sf {f}^{-1}(12) } :

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 2(12)- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 36- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 33

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postnew [5]

Answer:

The answer is D.

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