X = games won
y = games lost
x + y = 72
x = 2y + 15
2y + 15 + y = 72
3y + 15 = 72
3y = 72 - 15
3y = 57
y = 57/3
y = 19 <=== lost games
x = 2y + 15
x = 2(19) + 15
x = 53 <=== won games
The percentile associated with the mean must be high than 50%
-12/3<span>•(-8(-4)^2-6)+2 Original Equation
-12/3</span><span>•(-8+16-6)+2 Simplify the (-4)^2
-12/3</span><span>•(2)+2 Simplify everything inside the equation
-8+2 Using PEMDAS, you multiply -12/3</span><span>•(2)
-6 You add from there</span>
Wilson's question is not a statistical question because the students my not a have tall person in their class
In order to solve this we'll start by assigning variables to hamburgers and cheeseburgers, since these are what we're trying to find. Lets say x = hamburgers and y = cheeseburgers. So we know two things, we know that x+y= 763 (hamburgers plus cheeseburgers sold equals 763, and we know that y= x+63 (cheeseburgers sold equals 63 more than hamburgers sold). Now we have a system of equations. This can be solved most easily by rearranging each equation to each y, and then set them equal to each other:
x+y=763 -> y=763-x, and we already have y=x+63. Set them equal to each other:
x+63 = 763-x (add x to both sides) -> 2x+63 = 763 (subtract 63 from both sides) -> 2x = 700 (divide both sides by 2) x = 350. So we solved for x, which is hamburgers sold, which is what the question asks for, so your answer is 350 hamburgers were sold on Saturday
