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irina1246 [14]
2 years ago
9

An architectural drawing lists the scale as 1/4" = 1'. If a bedroom measures 634" by 412" on the drawing, how large is the bedro

om?

Mathematics
1 answer:
svp [43]2 years ago
6 0

For a bedroom measuring 6 3/4" by 4 1/2" on the drawing, the dimensions of the bedroom are 18 ft. by 27 ft.

Option (C) is correct.

In mathematics, a dimension is the length or width of an area, region, or space in one direction. It is just the measurement of an object's length, width, and height.

According to the question,

The scale of an architectural sketch is 1/4" = 1'. If, according to the drawing, a bedroom has the dimensions 6 3/4 by 4 1/2 inches.

Then, the dimensions of the bedroom in feets are calculated as follows:

As 1/4" = 1'

6 3/4" = 27'= 27 ft.

Similarly,

4 1/2" = 18' =18 ft.

Thus, the dimensions of the bedroom are: 18 ft. by 27 ft.

Learn more about dimensions here:

brainly.com/question/19819849

#SPJ1

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irinina [24]
Simple....

you have:

5x+2=4x-9

5x+2=4x-9
-4x         -4x

x+2=-9

x+2=-9
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x=-11

Thus, your answer.
7 0
3 years ago
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kumpel [21]
A+(-1.6)=-3.7
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Which point on the graph of g(x)=(1/5)^x? HELPP
Cloud [144]

Answer:

(-1,5) and (3, \frac{1}{125}) are points on the graph

Step-by-step explanation:

Given

g(x) = \frac{1}{5}^x

Required

Determine which point in on the graph

To get which of point A to D is on the graph, we have to plug in their values in the given expression using the format; (x,g(x))

A. (-1,5)

x = -1

Substitute -1 for x in g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^{-1}

Convert to index form

g(x) = 1/(\frac{1}{5})

Change / to *

g(x) = 1*(\frac{5}{1})

g(x) = 5

This satisfies (-1,5)

<em>Hence, (-1,5) is on the graph</em>

<em></em>

B. (1,0)

x = 1

Substitute 1 for x

g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^1

g(x) = \frac{1}{5}

<em>(1,0) is not on the graph because g(x) is not equal to 0</em>

C. (3, \frac{1}{125})

x = 3

Substitute 3 for x

g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^3

Apply law of indices

g(x) = \frac{1}{5} * \frac{1}{5} * \frac{1}{5}

g(x) = \frac{1}{125}

This satisfies (3, \frac{1}{125})

<em>Hence, </em>(3, \frac{1}{125})<em> is on the graph</em>

<em></em>

D.  (-2, \frac{1}{25})

x = -2

Substitute -2 for x

g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^{-2}

Convert to index form

g(x) = 1/(\frac{1}{5}^2)

g(x) = 1/(\frac{1}{5}*\frac{1}{5})

g(x) = 1/(\frac{1}{25})

Change / to *

g(x) = 1*(\frac{25}{1})

g(x) = 25

This does not satisfy  (-2, \frac{1}{25})

<em>Hence, </em> (-2, \frac{1}{25})<em> is not on the graph</em>

8 0
4 years ago
Ii) p – (p – q) – q – (q – p)
sashaice [31]

Answer:

-q + p

Step-by-step explanation:

p - (p - q) - q - (q - p) = p - p + <u>q -q</u> - q + p

                                = 0 + 0 - q + p

                               = -q + p

4 0
4 years ago
I need help too<br> please i will give brainly
ale4655 [162]

Answer:

Wait,so what exactly do I do? I can help i just need to know if i count the units or find the ploints.

Step-by-step explanation:

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