Refer to the number line. Find the coordinate of point Y such that the ratio of MY to YJ is 2:3
1 answer:
The coordinate of point Y such that the ratio of MY to YJ is 2:3 is 6.4
<h3>How to determine the point?</h3>The complete question is added as an attachment
The coordinates are given as:
M = 2
J = 18
The ratio is given as:
Ratio = 2 : 3
The location of the point Y is then calculated as:
Y = Ratio * (J - M)
This gives
Y = 2/(2 + 3) * (18 - 2)
Evaluate
Y = 2/5 * 16
This gives
Y = 6.4
Hence, the coordinate of point Y such that the ratio of MY to YJ is 2:3 is 6.4
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The answer is Option B
Step-by-step explanation:
Step 1: Group the given cubic polynomial into two sections.
So polynomial can be grouped as
Step 2:Find what's the common in each section.
In section the come term is
In section (8x + 48) the come term is 8
Step 3:Factor the commonalities out of the two terms.
Factoring out from the first section
, we get
Factoring out 8 from the second section(8x + 48) , we will get 8(x + 6).
Step 4: Combine the factors together for terms contains the same factor,
Combining we get,