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Sveta_85 [38]
3 years ago
15

John has $6 to buy school supplies. He buys 6 notebooks that are $0.52 each. He spends the remaining money buying erasers that a

re $0.16 each. If he has no money left over, how many erasers did he buy?
Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
5 0
John bought 18 erasers.



Explanation: He has $6.00

He spends $3.12 on notebooks
Then you do $6.00 - $3.12 and you get $2.88

If it’s ¢16 per eraser and he has no money left over after buying erasers than you would divide $2.88 by $0.16 which turns into 288 divided by 16 which comes out to 18.

Therefor John bought 18 erasers.
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Jason went to the Hamburger Shack twice last week.
WARRIOR [948]

Answer:

Cost of 1 hamburger = $1.3

Step-by-step explanation:

Assume;

Cost of 1 hamburger = a

Cost of 1 French fries = b

On first trip

3a + 4b = 7.10......eq1

On second trip

2a + b = 3.40....eq2

From eq2 x 4

8a + 4b = 13.6....eq3

From eq3 - eq1

5a = 6.5

a = 1.3

Cost of 1 hamburger = $1.3

7 0
3 years ago
Please someone know this ?
sladkih [1.3K]

Answer:

sas fact congruency

Step-by-step explanation:

angle and same side are given

both triangle have same side

3 0
3 years ago
A machine operation produces bearings whose diameters are normally distributed, with a mean of 0.497 inch and a standard deviati
eduard
Mean = 0.497 in, SD = 0.003 in
Required diameter ranges between 0.496 in and 0.504 in
Anything other diameter obtained is not acceptable.

That is;
P(x<0.496) and P(x>0.504) are not acceptable.

Now,
P(x<0.496) = P(Z< (0.496-0.497)/0.003)) = P(Z<-0.33)
From Z tables, P(Z<-0.33) = 0.3707

Similarly,
P(x>0.504) = P(Z> (0.504-0.497)/0.003)) = P(Z>2.33)
From Z tables, P(Z>2.33) = 1-0.9901 = 0.0099

Therefore, unacceptable proportion = P(x<0.496)+P(x>0.504) = 0.3707+0.0099 = 0.3806 or 38.06%
6 0
3 years ago
Garry has 15 apples he gives 8 away how many apples does Garry have left?
Anuta_ua [19.1K]

Answer:

7 apples left

Step-by-step explanation:

So he has 15 apples. IF he gives aways 8, he only has 15-8= 7 apples left

7 0
3 years ago
Read 2 more answers
Is the point (1,3) a solution to the linear equation 5x-9y=32? explain
harina [27]

There are many ways to check if the point (1,3) is a solution to the linear equation 5x-9y=32.

Let us check it by expressing y in terms of x.

The given expression is 5x-9y=32. If we add -5x to both sides we will get:

-9y=-5x+32

Multiplying both sides by -1 we will get:

9y=5x-32

In order to isolate y, we will divide both sides by 9 to get:

y=\frac{5}{9}x-\frac{32}{9}

Now let us plug in the given value of x=1 from the point (1,3). This should give us y=3. Let us see if we get y=3 when we plug x=1 in the above equation.

y=\frac{5}{9}\times 1-\frac{32}{9}=\frac{5-32}{9}

\therefore y=\frac{-27}{9}=-3

Thus, we see that when x=1, y=-3 and that y\neq 3 and hence we conclude that the point (1,3) is not a solution to the original given linear equation 5x-9y=32.

For a better understanding of the explanation given here a graph has been attached. As can be seen from the graph, (1,3) does not lie on the straight line that represents 5x-9y=32, but (1,-3) does lie on it as we had just found out.





3 0
3 years ago
Read 2 more answers
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