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serious [3.7K]
2 years ago
6

Solve for m and n I been stuck on this question for an hour

Mathematics
1 answer:
Crazy boy [7]2 years ago
3 0

Answer:

m = 10 , n = 5\sqrt{2}

Step-by-step explanation:

using the cosine and tangent ratio in the right triangle and the exact values

cos45° = \frac{1}{\sqrt{2} } and tan45° = 1 , then

cos45° = \frac{adjacent}{hypotenuse} = \frac{5\sqrt{2} }{m} = \frac{1}{\sqrt{2} } ( cross- multiply )

m = 5\sqrt{2} × \sqrt{2} = 5 × 2 = 10

-----------------------------------------

tan45° = \frac{opposite}{adjacent} = \frac{n}{5\sqrt{2} } = 1 , then

n = 5\sqrt{2}

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Y= -x-2;(2,4) a solution not a solution<br><br> show me step by step
Oxana [17]

Answer: not a solution


Step-by-step explanation:

Y= -x-2;(2,4)


4= -2-2


4=-4


The ordered pair is not a solution doesn't equal

4 0
3 years ago
I need help please and thank you
MrRa [10]

I will show you a way to do 1 and then you pratice with the rest and I'll check it and help you .

This is what I would do to make it easier

1. 7:15 to 11:16 then 12:05 to 6:10

- hours are on the left side-

1 - 7:15 to 8:15

2- 8:15 to 9: 15

3 - 9:15 to 10:15

4 - 10:15 to 11:15

16 - 15 = 1

4 hours and 1 minute

worked :12:05 - 6:10

1- 12:05 to 1:05

2- 1:05 to 2:05

3- 2:05 to 3:05

4 - 3:05 to 4:05

5- 4:05 to 5:05

6- 5:05 to 6:05

10 - 5 = 5

6 hours and 5 mins

4 + 6 = 10 hours

1 + 5 = 6 mins

10 hours and 6 minutes

6 0
3 years ago
The answer please please
Murrr4er [49]
The answer to that question is 4
3 0
4 years ago
Please help with this problem
fenix001 [56]

Answer:

y⁷/x⁵ , I hope this helps

4 0
3 years ago
Given the equation (x-a)^2(x-2)=x^3+bx^2+12x-72 find a and b
ivann1987 [24]
Isolate the variable by dividing each side by factors that don't contain the variable.

a=- \frac{ x^{2}- \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2} ,- \frac{ x^{2}+ \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2}

Solve for b by simplifying both sides of the equation then isolating the variable.

b= \frac{12}{x}+ \frac{72}{ x^{2} }-2+2a- \frac{4a}{x}+ \frac{ a^{2} }{x}- \frac{2a^{z} }{ x^{2} }

Hopefully i helped ^.^ Mark brainly if possible. Lol once again i saw the same question so why not answer it again!
 


3 0
3 years ago
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