Answer:
Step-by-step explanation: i cant help if you dont give the question:)
Answer:

The problem:
Find
if
,
, and
.
Step-by-step explanation:


Replace
in
with
since we are asked to find
:
![\sqrt[3]{x+3}=\sqrt[3]{g(x)+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B3%7D%3D%5Csqrt%5B3%5D%7Bg%28x%29%2B2%7D)
![\sqrt[3]{x+1+2}=\sqrt[3]{g(x)+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B1%2B2%7D%3D%5Csqrt%5B3%5D%7Bg%28x%29%2B2%7D)
This implies that 
Let's check:



![\sqrt[3]{(x+1)+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%28x%2B1%29%2B2%7D)
![\sqrt[3]{x+1+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B1%2B2%7D)
which is the required result for
.
This is not the answer, but I want to tell you that I can't see what the problem says. I would help you, but I can't.
We need the following to be true
a+2b = -a
a+4 = 2a - 3b
Let's look at the first equation.
a + 2b = -a
Subtract both sides by a
2b = -2a
b = -a
Substitute b= -a into the second equation
a+4 = 2a + 3a
a + 4 = 5a
4a = 4
a = 1
Just take the negative of that and you get the value of b.
b = -1
Your solution is a=1 and b = -1.
Have an awesome day! :)
The initial function is slope
=> slope = 7-1/6-0 = 6/6 = 1
Hope this helps you :)