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Elza [17]
3 years ago
15

Given the equation (x-a)^2(x-2)=x^3+bx^2+12x-72 find a and b

Mathematics
1 answer:
ivann1987 [24]3 years ago
3 0
Isolate the variable by dividing each side by factors that don't contain the variable.

a=- \frac{ x^{2}- \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2} ,- \frac{ x^{2}+ \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2}

Solve for b by simplifying both sides of the equation then isolating the variable.

b= \frac{12}{x}+ \frac{72}{ x^{2} }-2+2a- \frac{4a}{x}+ \frac{ a^{2} }{x}- \frac{2a^{z} }{ x^{2} }

Hopefully i helped ^.^ Mark brainly if possible. Lol once again i saw the same question so why not answer it again!
 


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Shkiper50 [21]

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For 6 months it would cost 14 x 6 = 84 + 25 = $109

The answer would be C.

8 0
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kirza4 [7]

Answer:

For the answer to the question above,

the Order the set of numbers from least to greatest: square root 64, 8 and 1 over 7, 8.14 repeating 14, 15 over 2

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Step-by-step explanation:

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Alexeev081 [22]
Pemdas

ok if we look at the first one
exponents first
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the first one is the answer
7 0
3 years ago
Four more than the quotient of a number and 3 is 2
Arturiano [62]

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Radda [10]

We have to trade 5 bunnies for a donkey.

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Since we now know a bunnies worth is 0.2 donkey

Therefore, (1/0.2=5) 5 bunnies to trade for a donkey.

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