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Katarina [22]
2 years ago
7

Find the three consecutive even integers such that one half of their sum is between 15 and 21. set up and solve a compound inequ

ality.
Mathematics
1 answer:
Kay [80]2 years ago
4 0

The even integers are 10,12 and 14.

Concept:  An integer is colloquially defined as a number that can be written without a fractional component. For example, 21, 4, 0, and −2048 are integers, while 9.75, 5+1/2, and √2 are not.

Let x,x+2,x+4 be the least, middle and greatest integer respectively.

According to the question,

15< x+x+2+x+4< 21

(3x+6)/2> 15      and    (3x+6)/2< 21

30< 3x+6                      3x+6> 42

24<3x                            3x<36

8<x                                x>12

x=10

x+2=12

x+4=14

Hence, The even integers are 10,12 and 14.

For more information about integers, visit

brainly.com/question/17695139

#SPJ4

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