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3 years ago

If Lisa ran 3 miles, how many meters did she run?

Mathematics

1 answer:

jeka57 [31]3 years ago

3 0

This is the answer 4828.03

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What is the simplified form of the expression?

Oduvanchick [21]

Answer:

the third one

$6a^{5} - 3a^{3} - 5a^{2} - 3b^{3}$

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Determine, to one decimal place, the length, width & height of the rectangular prism that would have the greatest volume, wi

Leya [2.2K]

Answer:

The length = The width = The height ≈ 5.8 cm

Step-by-step explanation:

The volume of a rectangular pyramid, V = l × w × h

The surface area of the pyramid = 2 × l × h + 2 × w × h + 2 × l × w = 200

∴ l × h + w × h + l × w = 200/2 = 100

We have that the maximum volume is given when the length, width, and height are equal and one length is not a fraction of the other. Therefore, we get;

At maximum volume, l = w = h

∴ l × h + w × h + l × w = 3·l² = 100

l² = 100/3

l = 10/√3

Therefore, the volume, v = l³ = (10/√3)³

The length = The width = The height = 10/√3 cm ≈ 5.8 cm

7 0

2 years ago

Which of the following expressions are equivalent to -19/8 x(-50)

dmitriy555 [2]

1. Move the negative sign to the left.

- $\frac{19}{8}$ $X$ *-50

2. Use this rule: $\frac{a}{b}$ $*$ $\frac{c}{d}$ = $\frac{ac}{bd}$

- $\frac{19x*-50}{8}$

3. Simplify - $\frac{-950x}{8}$

4. Move the negative sign to the left.

-(-950x/8)

5. Simplify 950x/8 to 475x/4

6. Remove parentheses.

5 0

2 years ago

Write a division problem whose quotient has its first digit in the hundreds place.

Dominik [7]

-- 500 divided by 5

-- 17,684 divided by 58.4

7 0

3 years ago

A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y=2−x2. What are the dimensions of su

Paul [167]

Answer:

Step-by-step explanation:

Given that a rectangle is inscribed with its base on the x-axis and its upper corners on the parabola

$y=2-x^2$

the parabola is open down with vertex at (0,2)

We can find that the rectangle also will be symmetrical about y axis.

Let the vertices on x axis by (p,0) and (-p,0)

Then other two vertices would be (p,2-p^2) (-p,2-p^2) because the vertices lie on the parabola and satisfy the parabola equation

Now width = $2-p^2$

Area = l*w = $2(2p-p^3)$

Use derivative test

I derivative = $2(2-3p^2)$

II derivative = $-12p$

Equate I derivative to 0 and consider positive value only since we want maximum

p = $\sqrt{\frac{2}{3} }$

Thus width= $\sqrt{\frac{2}{3} }$

Length = $2\sqrt{\frac{2}{3} }$

Width = $2-2/3 = 4/3$

3 0

3 years ago