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1 year ago

10. Which travels faster, a car that goes 200 miles in 2 hours, or a

Mathematics

1 answer:

umka21 [38]1 year ago

6 0

<h2>Answer:</h2>

<em>Question 10. </em><u><em>The truck travels faster</em></u><em>.</em>

<em>Question 11. </em><u><em>The slug travels faster</em></u><em>.</em>

<h2>Step-by-step explanation:</h2>

<h2><u>Question 10.</u></h2>

<u />

<h3>1. Find the velocity of each vehicle.</h3>

$Speed=\frac{distance}{time}$

$Speed_{Car} =\frac{200(miles)}{2(hours)}=100mi/h. \\\\ Speed_{Truck} =\frac{300(miles)}{2.5(hours)} =120mi/h.\\ \\$

<h3>2. Compare the velocities.</h3>

$Speed_{Car} =100mi/h < Speed_{Truck} =120mi/h.$

<em>Hence, the trucks travels faster than the car.</em>

<h2><u>Question 11.</u></h2>

<em>Apply the same method as in question 10.</em>

<h3>1. Find the velocity of each body.</h3>

<em /> $Speed_{snail}=\frac{20(cm)}{(3 min)} =6.67cm/min.\\ \\Speed_{slug}=\frac{15(cm)}{(2 min)} =7.5cm/min.$

<h3>2. Compare the velocities.</h3>

$Speed_{snail}=\frac{20(cm)}{(3 min)} =6.67cm/min < Speed_{slug}=\frac{15(cm)}{(2 min)} =7.5cm/min.$

Hence, the slug travels faster.

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Some body can help me with a geometric mean maze

Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

Theorem 1: The length of the altitude to the hypotenuse of a right triangle is the geometric mean of the lengths of the segments of the hypotenuse.

Theorem 2: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

1. Start point: By the 1st theorem,

$x^2=25\cdot (49-25)=25\cdot 24=5^2\cdot 2^2\cdot 6\Rightarrow x=5\cdot 2\cdot \sqrt{6}=10\sqrt{6}.$

2. South-East point from the Start: By the 2nd theorem,

$x^2=40\cdot (40+5)=4\cdot 5\cdot 2\cdot 9\cdot 5\Rightarrow x=2\cdot 5\cdot 3\cdot \sqrt{2}=30\sqrt{2}.$

3. West point from the previous: By the 2nd theorem,

$x^2=(32-20)\cdot 32=4\cdot 3\cdot 16\cdot 2\Rightarrow x=2\cdot 4\cdot \sqrt{6}=8\sqrt{6}.$

4. West point from the previous: By the 1st theorem,

$9^2=x\cdot 15\Rightarrow x=\dfrac{81}{15}=\dfrac{27}{5}=5.4.$

5. West point from the previous: By the 2nd theorem,

$10^2=8\cdot (8+x)\Rightarrow 8+x=12.5,\ x=4.5.$

6. North point from the previous: By the 1st theorem,

$x^2=48\cdot 6=6\cdot 4\cdot 2\cdot 6\Rightarrow x=6\cdot 2\cdot \sqrt{2}=12\sqrt{2}.$

7. East point from the previous: By the 2nd theorem,

$x^2=22.5\cdot 30=225\cdot 3\Rightarrow x=15\sqrt{3}.$

8. North point from the previous: By the 1st theorem,

$x^2=7.5\cdot 36=270\Rightarrow x=3\sqrt{30}.$

8. West point from the previous: By the 2nd theorem,

$x^2=12.5\cdot (12.5+13.5)=12.5\cdot 26=25\cdot 13\Rightarrow x=5\sqrt{13}.$

9. North point from the previous: By the 1st theorem,

$12^2=x\cdot 30\Rightarrow x=\dfrac{144}{30}=4.8.$

101. East point from the previous: By the 1st theorem,

$6^2=1.6\cdot (x-1.6)\Rightarrow x-1.6=22.5,\ x=24.1.$

11. East point from the previous: By the 2nd theorem,

$20^2=32\cdot (32-x)\Rightarrow 32-x=12.5,\ x=19.5.$

12. South-east point from the previous: By the 2nd theorem,

$18^2=x\cdot 21.6\Rightarrow x=15.$

13. North point=The end.

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2 years ago

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Answer:

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2 years ago

A rectangle has the following vertices. Find the area of the rectangle. (9, −1), (−1, 7), (−5, 2), (5, −6)

stiks02 [169]

Answer: 82 sq. units .

Step-by-step explanation:

Let A (9, −1), B (−1, 7), C(−5, 2), D(5, −6) are the vertices of rectangle.

Then we plot them on graph ( as provided in attachment)

Length = AB $=\sqrt{(9+1)^2+(-1-7)^2}$ units [By distance formula : $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ ]

$=\sqrt{(10)^2+(-8)^2}=\sqrt{100+64}=\sqrt{164}=2\sqrt{41}$ units

Width = BC = $\sqrt{(-1+5)^2+(7-2)^2}$ units

$=\sqrt{4^2+5^2}\\\\=\sqrt{16+25}\\\\=\sqrt{41}$

Area = length x width

= $2\sqrt{41}\times\sqrt{41}=2\times41= 82\text{ sq. units}$

Hence, the area of the rectangle is 82 sq. units .

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3 years ago

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Answer:

About 300 calories

The drawing will help

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2 years ago

The factory makes light bulbs the probability that a bulb is defective is 1/15 if 300 light bulbs are tested about how many are

irga5000 [103]

defective : working = 1/15 ( x20 ) 20/300
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