Question

Given that g(x)=3(x)^2-5(x)+1 g(1-t)

Answer 1

Answer: g(1-t)=3t^2-t-1

Step-by-step explanation:

g(x)=3(x)^2-5(x)+1

g(1-t)=3(1-t)^2-5(1-t)+1

g(1-t)=3(1-t)(1-t)-5-(-5t)+1

g(1-t)=3(1-t-t+t^2)-5+5t+1

g(1-t)=3(1-2t+t^2)-5+5t+1

g(1-t)=3-6t+3t^2-5+5t+1

g(1-t)=3-5+1-6t+5t+3t^2

g(1-t)=-1-t+3t^2

g(1-t)=3t^2-t-1