Given that g(x)=3(x)^2-5(x)+1
g(1-t)
1 answer:
Answer: g(1-t)=3t^2-t-1
Step-by-step explanation:
g(x)=3(x)^2-5(x)+1
g(1-t)=3(1-t)^2-5(1-t)+1
g(1-t)=3(1-t)(1-t)-5-(-5t)+1
g(1-t)=3(1-t-t+t^2)-5+5t+1
g(1-t)=3(1-2t+t^2)-5+5t+1
g(1-t)=3-6t+3t^2-5+5t+1
g(1-t)=3-5+1-6t+5t+3t^2
g(1-t)=-1-t+3t^2
g(1-t)=3t^2-t-1
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