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olasank [31]
2 years ago
7

3. Find the value of m for which the equation mx + 14 = 12 + 2 has one repeated root.

Mathematics
1 answer:
umka2103 [35]2 years ago
7 0

Using the discriminant of a quadratic equation, it is found that the quadratic equation would have one repeated solution for m = -3.

<h3>What is the quadratic equation?</h3>

The quadratic equation is given as follows:

mx² + 12x - 12.

<h3>What is the discriminant of a quadratic equation and how does it influence the solutions?</h3>

A quadratic equation is modeled by:

y = ax^2 + bx + c

The discriminant is:

\Delta = b^2 - 4ac

The solutions are as follows:

  • If \mathbf{\Delta > 0}, it has 2 real solutions.
  • If \mathbf{\Delta = 0}, it has 1 real solutions.
  • If \mathbf{\Delta < 0}, it has 2 complex solutions.

For this problem, the coefficients are:

a = m, b = 12, c = -12.

Hence the discriminant is:

b² - 4ac = 144 + 48m.

We want it to be of 0, hence:

144 + 48m = 0

m = -144/48

m = -3.

More can be learned about the discriminant of a quadratic equation at brainly.com/question/19776811

#SPJ1

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Step-by-step explanation:

This is a binomial distribution probability problem. The formula is:

P(x)=\frac{n!}{(n-x)!x!}p^{x}q^{n-x}

Where

n is the number of trials [here we are taking 8 person, so n = 8]

x is what we are looking for [in the problem]

p is the probability of success [ 15%, so p = 0.15

q is the probability of failure [q = 1-p = 0.85]

Now,

a)

We are looking for "no one" did fling, so x = 0

Let's put into formula and find out the probability:

P(x=0)=\frac{8!}{(8-0)!0!}(0.15)^{0}(0.85)^{8}\\P(x=0)=0.2725

So, the probability that no one has done a one-time fling is 0.2725

b)

Atleast 1 person means P(x ≥ 1).

This can be found by:

P(x ≥ 1) = 1 - P(x=0) = 1 - 0.2725 = 0.7275

THus, Probability that at least one person has done a one-time fling is 0.7275

c)

No more than 2 people means P (x≤2).

This is essentially

P ( x ≤ 2 ) = P(x=0) + P(x=1) + P(x=2)

P ( x = 0 ) is found in part (a), which is 0.2725

P (x = 1 ) and P(x=2) can be found using formula:

P(x=1)=\frac{8!}{(8-1)!1!}(0.15)^{1}(0.85)^{7}\\P(x=1)=0.3847

and

P(x=2)=\frac{8!}{(8-2)!2!}(0.15)^{2}(0.85)^{6}\\P(x=2)=0.2376

Thus,

P ( x ≤ 2 ) = P(x=0) + P(x=1) + P(x=2) = 0.2725 + 0.3847 + 0.2376 = 0.8948

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