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olasank [31]
1 year ago
7

3. Find the value of m for which the equation mx + 14 = 12 + 2 has one repeated root.

Mathematics
1 answer:
umka2103 [35]1 year ago
7 0

Using the discriminant of a quadratic equation, it is found that the quadratic equation would have one repeated solution for m = -3.

<h3>What is the quadratic equation?</h3>

The quadratic equation is given as follows:

mx² + 12x - 12.

<h3>What is the discriminant of a quadratic equation and how does it influence the solutions?</h3>

A quadratic equation is modeled by:

y = ax^2 + bx + c

The discriminant is:

\Delta = b^2 - 4ac

The solutions are as follows:

  • If \mathbf{\Delta > 0}, it has 2 real solutions.
  • If \mathbf{\Delta = 0}, it has 1 real solutions.
  • If \mathbf{\Delta < 0}, it has 2 complex solutions.

For this problem, the coefficients are:

a = m, b = 12, c = -12.

Hence the discriminant is:

b² - 4ac = 144 + 48m.

We want it to be of 0, hence:

144 + 48m = 0

m = -144/48

m = -3.

More can be learned about the discriminant of a quadratic equation at brainly.com/question/19776811

#SPJ1

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