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stiv31 [10]
3 years ago
13

A triangle has two sides of lengths 7 and 9. What value could the length of

Mathematics
1 answer:
Temka [501]3 years ago
7 0

Answer:

5, 13, 10, 8

Step-by-step explanation:

hello, so for this question keep in mind the triangle inequality theorem which states- a side must be smaller than the sum of the other two sides.

go through each of the choices.

a. 5+7=12 12>9

b.2+7=9 9>9 this cant be the answer since 9 is equal to nine, not greater than,

c. 13+7=20 20>9

d.10+7=17 17>9

e.8+7=15 15>9

f.22+7=29 29>9 although 29 is greater than 9, we also have to keep in mind that the other 2 sides must also be greater than the other side. so try 7+9= 16. 16 isnt greater than 22 so it can’t be one of the answers.

hope this helped :)

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<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

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<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

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