For compound interest, the formula is given below:
Amount = ![P(1+\frac{r}{100} )^{n}](https://tex.z-dn.net/?f=P%281%2B%5Cfrac%7Br%7D%7B100%7D%20%29%5E%7Bn%7D)
Here, P = 18,800
n = 2
r = 13/100
So, Amount = ![18,800(1+\frac{13}{100} )^{2}](https://tex.z-dn.net/?f=18%2C800%281%2B%5Cfrac%7B13%7D%7B100%7D%20%29%5E%7B2%7D)
![18,800(1.13)^{2}](https://tex.z-dn.net/?f=18%2C800%281.13%29%5E%7B2%7D)
= 18,800 × 1.2769
= 24005.72
Compound Interest = Amount - Principal
Compound Interest = 24005.72 - 18800
= 5205.72
Hence, the compound interest for Rs.18,800, calculated for 2 years at 13% rate of interest compounded annually is Rs.5205.72.
First term (a1) is -1
recursive formula goes like this
![a_n](https://tex.z-dn.net/?f=a_n)
is the nth term
![a_{n-1}](https://tex.z-dn.net/?f=a_%7Bn-1%7D)
is the term before that
we normally have
![a_n=f(a_{n-1})](https://tex.z-dn.net/?f=a_n%3Df%28a_%7Bn-1%7D%29)
we see each term is multipying by -3 to get next one
so that would be
![a_n=-3*a_{n-1}](https://tex.z-dn.net/?f=a_n%3D-3%2Aa_%7Bn-1%7D)
where a1=-1
the 3rd option is correct except that it is the explicit formula
so answer is 2nd one
Step-by-step explanation:
0 10
0-6
this is the answer. I am sure