<img src="https://tex.z-dn.net/?f=%5Csqrt%7B25%7D" id="TexFormula1" title="\sqrt{25}" alt="\sqrt{25}" align="absmiddle" class="l

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irga5000 [103]

3 years ago

atex-formula">

Mathematics

2 answers:

velikii [3]3 years ago

6 0

Answer:

Step-by-step explanation:

Calculate the square root of 25 and get 5.

marusya05 [52]3 years ago

6 0

5 I just thought of what # gets me to 25

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3 years ago

Write an integer for the situation.<br> A plane ascended 34,200 feet.

lesya692 [45]

Answer:

34,200

Step-by-step explanation:

Ascend means up so it's positive.

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3 years ago

Rewriting standard form to slope intercept

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3 0

3 years ago

Solve the equation without the use of a calculator. please Help!!! Thank you!!!<br> 12x^3-30x=5-2x^2

nata0808 [166]

So, since we have a cubic equation with 4 terms, the first thing we should try is factoring by grouping, so:

$12x^3+2x^2-30x+5 =0 \implies \\ 2x^2(6x+1)-5(6x+1)=0 \implies \\ (2x^2-5)(6x+1) = 0$

Now that we've factored our equation, we can use ZPP and break it up:

$2x^2-5 = 0 \implies \\ 2x^2=5 \implies\\ x^2=\frac{5}{2} \implies\\ x=\pm\frac{\sqrt{5}}{\sqrt{2}}=\pm\frac{\sqrt{10}}{2} \\ \\ 6x+1 =0 \implies \\ 6x=-1 \implies\\ x=\frac{-1}{6}$

So, our solutions are:

$x\in \{\frac{\sqrt{10}}{2},-\frac{\sqrt{10}}{2},-\frac{1}{6}\}$

4 0

3 years ago

How to solve x=6y-11 and 3x-2y=-1 by substitution

vagabundo [1.1K]

Substitute x into the second equation:
3(6y-11)-2y=-1
18y-33-2y=-1
16y=32
y=2
Then put the y value into the first equation to get x:
x=6(2)-11
x=1
There you go!

Please mark brainliest

7 0

3 years ago