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irga5000 [103]
2 years ago
9

atex-formula">
Mathematics
2 answers:
velikii [3]2 years ago
6 0

Answer:

5

Step-by-step explanation:

Calculate the square root of 25 and get 5.

marusya05 [52]2 years ago
6 0
5 I just thought of what # gets me to 25
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Find the coordinates of the midpoint of a segment with the given endpoints W(-12, -7), T(-8, -4)
jasenka [17]

Finding the midpoint coordinates of any segment really boils down to finding the midpoints of each individual coordinate.

The x-coordinates of the two points are -12 and -8 - the number halfway between those two is -10, so that'll be the midpoint's x-coordinate. The y-coordinates are -7 and -4 - -5.5 is halfway between these two, so the y-coordinate will be 5.5.

Putting the two together, the midpoint of the segment WT has the coordinates (-10, -5.5).

4 0
3 years ago
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How are real numbers used to describe real world situations?
makkiz [27]
For example, money. If you are buying a shirt, that costs $5.49, and a pair of shoes that costs $16.99, then that would be a real world situation. You would have spent $22.48.
5 0
2 years ago
The lateral area of a cone is 19.2π in2. The radius is 2.4 in. Find the slant height.
Alexus [3.1K]

The slant height of a cone with lateral surface are of 19.2π inches squared and radius of 2.4 inches is 8 inches.

<h3>Lateral surface area of a cone</h3>

The formula for the lateral surface area of a cone is described as follows:

Lateral area = πrl

where

  • r = base radius
  • l = slant height

Therefore,

Lateral area = 19.2π inches²

r = 2.4 inches

Lateral area = π × 2.4 × l

19.2π = 2.4πl

divide both sides by 2.4π

l = 19.2π / 2.4π

l = 8 inches

learn more on cone here: brainly.com/question/27170515

5 0
2 years ago
How to find z statistic for test?
alexandr402 [8]
The z-score is calculated by the formula (x - mu)/sigma, where x is the value, mu is the mean, and sigma is the standard deviation.
3 0
2 years ago
Is -2 a solution to 4x^(3)-x^(2)+16x-4
sergiy2304 [10]

Answer:

Not a solution

Step-by-step explanation:

In order for x=-2 to be a solution, the result after substituting must be 0:

4(-2)^3-(-2)^2+16(-2)-4\stackrel{?}{=}0

4(-8)-4-32-4\stackrel{?}{=}0

-32-40\stackrel{?}{=}0

-72\neq0

Therefore, x=-2 is not a solution to 4x^3-x^2+16x-4

3 0
2 years ago
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