Answer:
there is 3 solutions
Step-by-step explanation:
Let AB extended intersect DC extended at point E
<span>We now have right triangle BEC with E = 90 degrees </span>
<span>For triangle BEC: </span>
<span>Exterior angle at E = 90 </span>
<span>Exterior angle at C = 148 (given) </span>
<span>Exterior angle of all polygons add up to 360 degrees </span>
<span>Exterior angle at B = 360−148−90 = 122 </span>
<span>So in quadrilateral ABCD </span>
<span>B = 122 </span>
<span>D = 360−44−148−122 = 46</span>
In this question, we have to fin the line of intersection of the planes A and QRV.
We have to see the given figure and find the line on which the two planes A and QRV meets.
Lines SR,TS, WT and WQ are not on plane QRV.
The only line which passes through both planes is QR.
And that's the line of intersection of the two planes.
Answer:
x=5.12
Step-by-step explanation:
35.16= 4.44+6x
30.72=6x
5.12=x
x=5.12
Hope this helps :)