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Scorpion4ik [409]
3 years ago
12

Arrange the 9 digits in three arithmetic sums. Using three of the four operations of addition, subtraction, multiplication, or d

ivision. Use no signs except the signs using those operations. Here is an example
You must use digits 1 - 9 and only ONCE

3 + 4 = 7

9 - 8 = 1

30 / 6 = 5

The above example is not correct, because it does not contain 2, and three is repeated.
Mathematics
1 answer:
aleksklad [387]3 years ago
7 0

Answer:

i. 5 + 4 = 9

ii. 2 x 3 = 6

iii. 8 - 7 = 1

Step-by-step explanation:

Given: The basic arithmetic operations: addition, subtraction, multiplication or division.

           Digits from 1 - 9

Using three arithmetic operations - addition, subtraction, multiplication, and the given digits, the following three expressions can be formed:

i. 5 + 4 = 9

ii. 2 x 3 = 6

iii. 8 - 7 = 1

It can be observed that there is no repetition of digits in the above expressions as required.

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What is the solution set for 9x2-25=0
Alexandra [31]

Answer: i hope i helped if not im truly sorry

Solving for 9x^2 - 25 = 0

Standard form:

9x2 − 25 = 0

Solutions based on quadratic formula:

x1  

= −0 − √ 02 − 4×9×(−25)  

2×9

= 0 − 30 × √ 1  

18

≈ −1.667

x2  

= −0 + √ 02 − 4×9×(−25)  

2×9

= 0 + 30 × √ 1  

18

≈ 1.667

Extrema:

Min = (0, −25)

Step-by-step explanation: im not dumb and im not smart

4 0
3 years ago
Help pleeeeaaaaaasssseeee
castortr0y [4]
You first need to know how many eggs there are altogether  -   72*36 = 2,592.
Then divide the answer by the number of stops (6)  -  2,592/6 = 432 are 'dropped off' at each stop. The answer is letter C

Hope this helps! :)
4 0
3 years ago
I need help with this exercise on Simplifying Logarithms.
Ainat [17]

Answer:

  e^6 ≈ 403

Step-by-step explanation:

You want the value of e^(4x-2) when x = 2.

<h3>Evaluation</h3>

Put 2 where x is in the expression and do the arithmetic.

  e^(4·2 -2) = e^6 ≈ 403.429

The value of the expression is about 403.

8 0
1 year ago
Which statement is true about the polynomial after it has been simplified. -10m^4n^3+8m^2n^6-6m^2n^6
laila [671]

Answer: 2m^2n^3 x ( -5m^2 + 4n^2 -3n^2 )

Step-by-step explanation:

<em>ok</em><em>,</em><em> so just let me</em><em>,</em><em> uh</em><em>,</em><em> make this a little easier on my eyes lol:</em>

-10m^4n^3+8m^2n^6-6m^2n^6 ----> (-10m^4)(n^3) + (8m^2)(n^6) - (6m^2)(n^6)

<em>I just put in parentheses. nothing changed. just parentheses. </em>

Since the leading coefficients, -10 , 8 , and 6 are multiples of two,

we can take out 2 from each... [-10/2 = 5 , 8/2 = 4 , 6/2 = 3 ]

= 2 x [ (-5m^4)(n^3) + (4m^2)(n^6) - (3m^2)(n^6) ]

Looking at it now...

<em>we can take out m^2 from each... </em>m^4 , m^2 , and m^2

m^2 [m^2 , 1 , 1]

since    m^4 /m^2 = m^2 , m^2 /m^2 = 1 , m^2 /m^2 = 1

= 2(m^2) x [ (-5m^2)(n^3) + (4x1)(n^6) - (3x1)(n^6) ]

= 2(m^2) x [ (-5m^2)(n^3) + (4)(n^6) - (3)(n^6) ]

Finally, one more step...

<em>we can take out n^3 from each term.... </em>n^3 , n^6 , and n^6

n^3 [1 , n^2 , n^2] since n^3 /n^3 = 1 , n^6 /n^3 = n^2 , n^6 /n^3 = n^2

= 2(m^2)(n^3) [ (-5m^2)(1) + (4)(n^2) - (3)(n^2) ]

= 2m^2n^3 x [ (-5m^2) + (4n^2) - (3n^2) ]

= 2m^2n^3 x ( -5m^2 + 4n^2 -3n^2 )

ANSWER: 2m^2n^3 x ( -5m^2 + 4n^2 -3n^2 )

<em>keep this parentheses. seriously. </em>

7 0
3 years ago
construct a 90% confidence interval of the population proportion using the giver information x=74 n=150
FrozenT [24]

Answer:

The 90% confidence interval of the population proportion is (0.43, 0.56).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population proportion <em>p</em> is:

CI=\hat p\pm z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}

The information provided is:

<em>X</em> = 74

<em>n</em> = 150

Confidence level = 90%

Compute the value of sample proportion as follows:

\hat p=\frac{X}{n}=\frac{74}{150}=0.493

Compute the critical value of <em>z</em> for 90% confidence level as follows:

z_{\alpha/2}=z_{0.10/2}=z_{0.05}=1.645

*Use a <em>z</em>-table.

Compute the 90% confidence interval of the population proportion as follows:

CI=\hat p\pm z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}

     =0.493\pm 1.645\times \sqrt{\frac{0.493(1-0.493)}{150}}\\\\=0.493\pm 0.0672\\\\=(0.4258,\ 0.5602)\\\\\approx (0.43,\ 0.56)

Thus, the 90% confidence interval of the population proportion is (0.43, 0.56).

3 0
3 years ago
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