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Mariana [72]
2 years ago
14

8. How much energy does a 12 V battery in your car use to move 2.5 C through the electrical

Mathematics
1 answer:
I am Lyosha [343]2 years ago
6 0

The energy required is 30 watts second.

In order to accomplish work and to produce heat and light, energy must be transferred to a body or to a physical system. Energy is the quantitative attribute that does this. Energy is a preserved resource; according to the rule of conservation of energy, energy can only be transformed from one form to another and cannot be created or eliminated.

The voltage of a battery is 12 V and;

The charge is 2.5C.

Now, energy can be defined as the product of voltage and charge.

Therefore,

E = V × C

E = 12 × 2.5

E = 30 watt second

Hence, the energy needed by the 12 V battery to move 2.5 C through the electrical circuit is 30 watts second.

Learn more about energy here:

brainly.com/question/13881533

#SPJ9

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The school that Stefan goes to is selling tickets to a choral performance. On the first day of ticket sales the school sold 3 se
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Answer: the price of a senior citizen's ticket is $8.

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Let x represent the price of a senior citizen's ticket.

Let y represent the price of a child's ticket.

On the first day of ticket sales, the school sold 3 senior citizen tickets and 1 child ticket for a total of $38. It means that

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Answer:

\rm\displaystyle (x  +  2{)}^{2}  + (y  + 5 {)}^{2}  =  {1}^{}

\rm\displaystyle (x - 7{)}^{2}  + (y  + 3{)}^{2}  =  { 7 }

Step-by-step explanation:

<h3>QUESTION-1:</h3>

we are given the center and the redious of a circle equation

remember that,

\rm\displaystyle E _{c} :(x - h {)}^{2}  + (y - k {)}^{2}  =  {r}^{2}

where (h,k) is the centre coordinate and r is redious of the circle

given that, h=-2 , k=-5 and r=1

Thus substitute:

\rm\displaystyle (x - ( - 2){)}^{2}  + (y - ( - 5) {)}^{2}  =  {1}^{2}

simplify:

\rm\displaystyle (x  +  2{)}^{2}  + (y  + 5 {)}^{2}  =  {1}^{}

<h3>QUESTION-2:</h3>

Likewise

\rm\displaystyle E _{c} :(x - h {)}^{2}  + (y - k {)}^{2}  =  {r}^{2}

given that,h=7,k=-3 and r=√7

substitute:

\rm\displaystyle (x - (7{))}^{2}  + (y - ( - 3){)}^{2}  =  { \sqrt{7}  ^{2}   }

simplify:

\rm\displaystyle (x - 7{)}^{2}  + (y  + 3{)}^{2}  =  { 7 }

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2 years ago
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