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3 years ago

What is the domain of the relation?

Mathematics

1 answer:

Thepotemich [5.8K]3 years ago

8 0

Answer: $-4$

Step-by-step explanation:

Domain: x-axis

Range: y-axis

The relation graph shows the points in which the domain is located. To find the Domain, go to the point in the x-axis (the horizontal line) and note the number where the point lies. For this question, the point on the left side of the graph lies on negative four ( $-4$ ), and on the right side, the point is on 6. Therefore, the domain of this relation is negative four is greater than/equal to x is less than/equal to six. It could also be written like this: $-4\leq x\leq 6$ .

Learn more: brainly.com/question/24574301

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What is the the area of the triangle in the composite figure above?

Flauer [41]

Answer:

$10 in^{2}$

Step-by-step explanation:

Subtract 13 from 17 to get the length of the base. Then add the 1, 1, and 3 together to get the height. Then you use the area formula for a triangle.

8 0

3 years ago

a cylinder shaped can needs to be constructed to hold 400 cubic centimeters of soup. the material for the sides of the can costs

fredd [130]

The dimensions of the can are radius of can = 4cm and

height of can = 78.6cm

What is the volume of cylinder?

A cylinder can be seen as a collection of multiple congruent disks, stacked one above the other. In order to calculate the space occupied by a cylinder, we calculate the space occupied by each disk and then add them up.

Thus, the volume of the cylinder can be given by the product of the area of base and height.

Volume of cylinder = πr²h

According to the given question:

We have V cylinder = V = 400cc

We will first find the areas involved

Let x = radius of base then area of the base = π*x² and this is the area of the top too

For lateral area we need to get h the height of the cylinder as function of x

V = πx²h ⇒ h= v/πx² ⇒ h = 400/πx²

Now the total area of the cylinder is:

A(x) = Area of the base + area of the top + lateral area

A(x) = 2*π*x² + 2πx h ⇒ A(x) = 2*π*x² + 2πx (V/πx² )

A(x) = 2*π*x² + 800/x

Taking derivatives:

A´(x) = 4πx - 800/x²

A´(x) = 0 4πx - 800/x² =0 ⇒ πx - 200/x² = 0

( πx³ - 200 )/ x² = 0

πx³ - 200 = 0

x = 4 cm

and h = 400/πx² ⇒ h = 78.6 cm

To know more about volume of cylinder visit

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3 0

1 year ago

Solve the equation on the interval [0,2π]

WARRIOR [948]

$\bf 16sin^5(x)+2sin(x)=12sin^3(x)
\\\\\\
16sin^5(x)+2sin(x)-12sin^3(x)=0
\\\\\\
\stackrel{common~factor}{2sin(x)}[8sin^4(x)+1-6sin^2(x)]=0\\\\
-------------------------------\\\\
2sin(x)=0\implies sin(x)=0\implies \measuredangle x=sin^{-1}(0)\implies \measuredangle x=
\begin{cases}
0\\
\pi \\
2\pi 
\end{cases}\\\\
-------------------------------$

$\bf 8sin^4(x)+1-6sin^2(x)=0\implies 8sin^4(x)-6sin^2(x)+1=0$

now, this is a quadratic equation, but the roots do not come out as integers, however it does have them, the discriminant, b² - 4ac, is positive, so it has 2 roots, so we'll plug it in the quadratic formula,

$\bf 8sin^4(x)-6sin^2(x)+1=0\implies 8[~[sin(x)]^2~]^2-6[sin(x)]^2+1=0
\\\\\\
~~~~~~~~~~~~\textit{quadratic formula}
\\\\
\begin{array}{lcccl}
& 8 sin^4& -6 sin^2(x)& +1\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array} 
\qquad \qquad 
sin(x)= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}
\\\\\\
sin(x)=\cfrac{-(-6)\pm\sqrt{(-6)^2-4(8)(1)}}{2(8)}\implies sin(x)=\cfrac{6\pm\sqrt{4}}{16}
\\\\\\
sin(x)=\cfrac{6\pm 2}{16}\implies sin(x)=
\begin{cases}
\frac{1}{2}\\\\
\frac{1}{4}
\end{cases}$

$\bf \measuredangle x=
\begin{cases}
sin^{-1}\left( \frac{1}{2} \right)
sin^{-1}\left( \frac{1}{4} \right)
\end{cases}\implies \measuredangle x=
\begin{cases}
\frac{\pi }{6}~,~\frac{5\pi }{6}\\
----------\\
\approx~0.252680~radians\\
\qquad or\\
\approx~14.47751~de grees\\
----------\\
\pi -0.252680\\
\approx 2.88891~radians\\
\qquad or\\
180-14.47751\\
\approx 165.52249~de grees
\end{cases}$

3 0

3 years ago

Ok ong i'm struggling and need help i've been up all night- Ill give brainlyest!!

Ipatiy [6.2K]

Answer:

Step-by-step explanation

- 7(6x-1)+x=36

=> 42x - 7 + x = 36
=> 43x - 7 = 36
=> 43x = 36 + 6 = 43
=> x = 43 / 43 = 1

- 11-2(8+3p)=7²

=> 11 - 16 - 6p = 7^2
=> 11 - 16 - 6p = 49
=> -5 - 6p = 49
=> -6p = 49 + 5 = 54
=> p = (54) / (-6) = - 9

- 1/4(5b+11)=19

=> (5/4)b + (11/4) = 19
=> (5/4)b = 19 - (11/4) = 65 /4
=> b = (65/4) / (5/4) => (65/4) * (4/5) = 13

- 2/7(4m-18)=12

=> (8/7)m - (36/7) = 12
=> (8/7)m = 12 + (36/7) = 120/7
=> m = (120/7) / (8/7) = 120 /8 = 15

3 0

3 years ago

What is this question?? (needing help)

Free_Kalibri [48]

468 x 0.001 = 0.468

46.8 x 0.1 = 4.68

4.68 x 10^3 = 4680

0.468 x 10^2 = 46.8

Hope this helps!

5 0

3 years ago

Read 2 more answers