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erma4kov [3.2K]
3 years ago
10

4 ^sqrt 400/ 4^ sqrt 5

Mathematics
1 answer:
Lina20 [59]3 years ago
7 0
4^ sqrt(400) / (4^ sqrt(5))
= 4^20/ 4^ sqrt(5)
= 4^ (20- sqrt(5)

The final answer is 4^ (20- sqrt(5)~
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Please help, i’m about to cry. HELP
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Answer:59 degrres and 118 degress

Step-by-step explanation:

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99 points AND BRAINLIEST answer to the person who can do this for me. I WILL REPORT ANY DUMB ANSWERS! PLEASE HELP ASAP!
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ΔADC ≅ ΔBCD (SAS congruency)

∠AED ≅ ∠BEC (opposite angles)

ΔAED ≅ ΔBEC (ASA congruency)

Therefore DE <span>≅ CE (corresponding sides of the two congruent triangles AED and BEC)</span>
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What happens when a triangle is dilated using one of the vertices as the center of the dilation? Complete
Yuki888 [10]

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The sides of the triangles adjacent to the center of dilation will be collinear. The third sides of the pre-

image and image will be “parallel”

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3 years ago
I need help with these questions
inysia [295]

Answer:

28. m<A=20°, m<B=70°

32. m<A=103°, m<B=77°

Step-by-step explanation:

complementary angle=a+b=90°

supplementary angle=a+b=180°

28. A+B=90°

      5x+17x+2=90°

      22x+2=90°

      22x=90-2

      22x=88

        22x/22=88/22

      x=88/22=<u>4</u>

m<A=5x=5*4=<u>20°</u>

m<B=17x+2=17*4+2=68+2=<u>70°</u>

         <u>Check</u>

A+B=90°

20+70=90°

<u>90°=90°</u>

32. A+B=180°

     x+11+x-15=180°

     2x-4=180°

     2x=180+4

     2x=184

     2x/2=184/2

     x=184/2

     x=<u>92</u>

m<A=x+11=92+11=<u>103°</u>

m<B=x-15=92-15=<u>77°</u>

     <u>Check</u>

A+B=180°

103+77=180°

<u>180°=180°</u>

6 0
3 years ago
Find two positive consecutive integers such that the square of the first added to three times the second is 24
Naddika [18.5K]

Answer:

3 and 5

Step-by-step explanation:

Let the two consecutive odd integers be x and x + 2.

Now,

The given statement is

x^2 + 3 \times (x+2)=24\\x^2 + 3x+6-24 = 0 \\x^2 + 3x-18 = 0\\x^2+6x-3x-18=0\\x(x+6)-3(x+6)=0\\(x-3)(x+6)=0\\x=3,-6

Taking x=3.

Hence, two consecutive odd integers are 3 and 5.

7 0
3 years ago
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