answer is already correctly displayed in the photo
most of the members of the species would die but somewhat survive
Attached are two images concerning DNA.
The first image is a diagram that illustrates the base paring of DNA. First, there is the ribose-phosphate backbone that keeps the DNA together. Then the bases thymine and adenine are joined together by two hydrogen bonds. On the other hand, the bases guanine and cytosine are joined together by three hydrogen bonds.
The second image shows the helical structure of the DNA.
Frequency of allele a1 is 75%, p=0.75
Frequency of allele a2 is 25%, q=0.25
If a population is in Hardy-Weinberg equilibrium then:
p2+2pq+q2=1
<span>p2 is the frequency of genotype a1a1 (homozygous),</span>
2pq is the frequency of genotype a1a2 (heterozygous),
q2 is the frequency of genotype a2a2
<span>The proportion of individuals with genotype a1a2 is then 2*0.75*0.25=0.375 (37.5%).</span>