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TiliK225 [7]
1 year ago
14

Question Which sequence of transformations maps pre-image ABC to image A′B′C′ ? Triangle ABC was reflected over the y-axis and t

hen dilated by a scale factor of 2. Triangle A B C, was reflected over the , y, -axis and then dilated by a scale factor of 2. Triangle ABC was reflected over the y-axis and then translated 2 units up and 2 units to the right. Triangle A B C, was reflected over the , y, -axis and then translated 2 units up and 2 units to the right. Triangle ABC was rotated 90° counterclockwise and then dilated by a scale factor of 2. Triangle A B C, was rotated 90° counterclockwise and then dilated by a scale factor of 2. Triangle ABC was rotated 90° counterclockwise and then translated 2 units up and 2 units to the right. Triangle A B C, was rotated 90° counterclockwise and then translated 2 units up and 2 units to the right.

Mathematics
1 answer:
Stells [14]1 year ago
7 0

The sequence of transformations was Triangle ABC was reflected over the y-axis and then translated 2 units up and 2 units to the right.

<h3>What is a transformation?</h3>

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, translation, rotation and dilation.

Rigid transformation is the transformation that does not change the shape or size of a figure. Examples of rigid transformations are <em>translation, reflection and rotation</em>.

Find out more on transformation at: brainly.com/question/4289712

#SPJ1

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We can first calculate all the possible sums and then determine the set of possible outcomes.
Possible sums are:
1+2 = 3
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3+2 = 6
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From the above possibilities, the outputs would belong to the set:
<span>{3, 4, 5, 6, 7, 8, 9, 10, 11, 12}</span>
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And 18 ounce box of raisins cause $2.88 a 24 ounce box of raisins cost $3.60 which one is the better deal
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the 24-ounce box

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While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
3 years ago
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