Question

Please resolve this problem for me! I've been having trouble with this for a while.

Answer 1

Answer:

a) 41

b) -31

c) 25/3

Step-by-step explanation:

The instructions explain what a function is pretty clearly.

Basically, whatever is in the parentheses next to the $f$, you plug in to the expression that is the function.

ex:     $f(x) = x + 4$

        $f(5) = 5 + 4 = 9$

Okay, onto the problems:

a) $f(x) = 3x - 1$

First, plug in 14, since that is given:

$f(14) = 3(14) - 1$

and solve.

$f(14) = 42 - 1$

$f(14) = 41$

So, 41 is the answer to a.

b) Do the same thing you did in problem a. Plug in the number inside the parentheses and solve.

$f(-10) = 3(-10) - 1$

$f(-10) = -30 - 1$

$f(-10) = -31$

-31 is the answer to b.

c) For this problem, you have to do a bit of algebra.

First, take the base function f(x):

$f(x) = 3x - 1$

Then, set f(x) = 24:

$24 = 3x - 1$

and solve by isolating x.

$25 = 3x$

$\dfrac{25}{3} = x$

$x = \dfrac{25}{3}$

25/3 is the answer to c.