P(x) = 2x^2 - 4x^2 - 9
g(x) = x - 3
q(x) = 2x^2 + 2x + 6
r(x) = 9
First, find the asymptotes.
When does f(x) become undefined? When the numerator is 0
0=4x-4
4=4x
x=1
Therefore, x cannot be 1, this is a horizontal asymptote.
We also know that when the degree of x in the numerator is smaller than the degree of x in the denominator, y=0.
Now that we have the horizontal asymptotes, find a third point to draw the graph.
If x=2,
f(2)=-3/4(2)-4
=-3/4
Be sure to include this points in your graph.
Hope I helped :)
For this problem, here’s how you do it.