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kirza4 [7]
2 years ago
15

Does anyone know the answer to this ??? I got the first part of it, help with the second part pls !!!

Mathematics
1 answer:
Ad libitum [116K]2 years ago
5 0

Solving the quadratic function, it is found that the particle returns to the ground after 7 seconds.

<h3>What is the quadratic function for the particle's height?</h3>

The particle's height after t seconds is modeled by the following equation:

s(t) = -16t² + v(0)t.

In which v(0) is the initial velocity of the particle, which in this problem is of 112 ft/s, hence:

s(t) = -16t² + 112t.

The particle hits the ground when s(t) = 0, hence:

s(t) = 0

-16t² + 112t = 0

-16t(t - 7) = 0.

Hence the non-trivial solution is:

t - 7 = 0 -> t = 7.

The particle returns to the ground after 7 seconds.

More can be learned about quadratic functions at brainly.com/question/24737967

#SPJ1

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An article gave the following summary information for fracture strengths (MPa) of n = 196 ceramic bars fired in a particular kil
Oliga [24]

Answer:

54.80 MPa to 55.92 MPa

Step-by-step explanation:

Sample mean fracture strength (x) = 55.36 MPa

Sample standard deviation (s) = 3.99 MPa

Sample size (n) = 196.

The upper and lower bounds for a 95% confidence interval are given by:

U=x+1.960*\frac{s}{\sqrt{n}} \\L=x-1.960*\frac{s}{\sqrt{n}}

The upper and lower bounds of the confidence interval are;

U=55.36+1.960*\frac{3.99}{\sqrt{196}}\\U= 55.92\\L=55.36-1.960*\frac{3.99}{\sqrt{196}}\\L= 54.80\\

The 95% confidence interval for true average fracture strength is 54.80 MPa to 55.92 MPa

4 0
4 years ago
Suppose that X is a random variable with mean 30 and standard deviation 4. Also suppose that Y is a random variable with mean 50
Vladimir79 [104]

Answer:

a) Var[z] = 1600

    D[z] = 40

b) Var[z] = 2304

    D[z] = 48

c) Var[z] = 80

    D[z] = 8.94

d) Var[z] = 80

    D[z] = 8.94

e) Var[z] = 320

    D[z] = 17.88

Step-by-step explanation:

In general

V([x+y] = V[x] + V[y] +2Cov[xy]

how in this problem Cov[XY] = 0, then

V[x+y] = V[x] + V[y]

Also we must use this properti of the variance  

V[ax+b] = a^{2}V[x]

and remember that

standard desviation = \sqrt{Var[x]}

a) z = 35-10x

   Var[z] = 10^{2} Var[x] = 100*16 = 1600

   D[z] = \sqrt{1600} = 40

b) z = 12x -5

   Var[z] = 12^{2} Var[x] = 144*16 = 2304

   D[z] = \sqrt{2304} = 48

c) z = x + y

   Var[z] =  Var[x+y] = Var[x] + Var[y] = 16 + 64 = 80

   D[z] = \sqrt{80} = 8.94  

d) z = x - y

   Var[z] =  Var[x-y] = Var[x] + Var[y] = 16 + 64 = 80

   D[z] = \sqrt{80} = 8.94

e) z = -2x + 2y

   Var[z] = 4Var[x] + 4Var[y] = 4*16 + 4*64 = 320

  D[z] = \sqrt{320} = 17.88

   

7 0
3 years ago
Y= 3/4x - 10<br><br> Please Help me ASAP
guajiro [1.7K]

Answer:

solving for x?

if so x=y+133/10

Step-by-step explanation:

7 0
3 years ago
Write an expression to<br> represent the perimeter of<br> the rectangle:<br> 3* +10<br> * +5
Schach [20]

Answer:

the perimeter is 18

Step-by-step explanation:

3 0
3 years ago
The sixth grade is raising money for the local animal shelter. So far they have raised $320, which is 40% of their goal. How muc
Lady_Fox [76]
They hope to raise 800 dollars.
4 0
3 years ago
Read 2 more answers
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