You are looking for three consecutive integers whose sum is 93. First, divide 93 by 3 and get 31. Go one above 31 and one below. You get 30, 31 and 32 which sum to 93.
Answer:
Height should be ≤ 9 inches.
Step-by-step explanation:
Given:
Frank is making a pennant in the shape of a triangle for his senior class photo.
Base of triangle = 6 in
Area of triangle ≤ 27 
Let height of the triangle be h
Now we now that,
Area of triangle = 
Hence the height of the triangle must be at most or ≤ 9 inches.
Answer:
a). m∠AED = 70°
b). x = 10°
Step-by-step explanation:
a). Quadrilateral ABDE is a cyclic quadrilateral.
Therefore, by the theorem of cyclic quadrilateral,
Sum of either pair of opposite angle is 180°
m(∠AED) + m(∠ABD) = 180°
m(∠AED) = 180° - 110°
m(∠AED) = 70°
Since, ∠AED ≅ ∠EAD
Therefore, m∠AED = m∠EAD = 70°
b). By triangle sum theorem in ΔABD,
m∠ABD + m∠BDA + m∠DAB = 180°
110° + 40° + m∠DAB = 180°
m∠DAB = 180° - 150°
m∠DAB = 30°
m∠BAE = m∠EAD + m∠BAD
= 70° + 30° = 100°
By angle sum theorem in ΔACE,
m∠EAC + m∠AEC + m∠ACE = 180°
100° + 70° + x° = 180°
x = 180° - 170°
x = 10°
Answer:
X=45
Step-by-step explanation:
Lines AC and CD meet at a right angle so you half 90 =45
Answer:
The probability that a student pick from this group at random either has blue or brown eyes is
P = 40/65 = 0.6154
P = 61.54%
Corrected question;
In a group of 65 students 10 have brown eyes and 30 have blue eyes. Find the Probability that a student pick from this group at random either has blue or brown eyes
Step-by-step explanation:
Given;
Total number of students = 65
Number of students with either blue or brown eyes;
= 10+30 = 40
The probability that a student pick from this group at random either has blue or brown eyes is
P = 40/65 = 0.6154
P = 61.54%
