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GuDViN [60]
1 year ago
13

Phospholipids are found in plasma membranes. are water-soluble. contain subunits called amino acids. are fat-soluble vitamins. a

re a type of steroid.
Biology
1 answer:
KengaRu [80]1 year ago
5 0

The correct option is (A). Are found in Plasma membrane

Phospholipids are the major constituent of the plasma membrane.

<h3>What are phospholipids' primary purposes?</h3>
  • The primary component of the plasma membrane is phospholipids. They are made up of fatty acid chains joined to a glycerol or other similar backbone, just like fats.
  • The glycerol backbone's third carbon is bonded to a phosphate group, hence there are only two fatty acids connected as opposed to three.
  • An alcohol is added to the phosphate group to change it. Both hydrophilic and hydrophobic areas can be found in phospholipids. While the phosphate is hydrophilic and interacts with water, the fatty acid chains are hydrophobic and keep themselves away from it.
  • A membrane with a bilayer of phospholipids surrounds each cell. The phosphate group can face either the outside environment or the inside of the cell, both of which are watery, as opposed to the fatty acids of phospholipids, which face within, away from water.

Learn more about the Plasma membrane with the help of the given link:

brainly.com/question/14727404

#SPJ4

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if a virus enters my body will it enter and leave alone or will it enter and infect cells please i need help
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Read 2 more answers
Duchenne muscular dystrophy is an X-linked recessive disease. A phenotypically normal couple wants to start a family. The woman’
Andreyy89

Answer:

\frac{1}{8}

Explanation:

From the question: Duchenne muscular dystrophy is an X-linked recessive disease.

Now for an X-linked recessive disorder to be affected by a male individual; it only requires the presence of only one copy of the recessive allele of the disease to be present BUT in a female individual. both copies of the recessive allele must be present.

Let the X-linked recessive disease(i.e Duchenne muscular dystrophy) be = (ⁿ)

However, we are told that the couples are normal and are unaffected. Therefore;

the male partner (XY) will be:   X^NY

the female partner (XY) will be: X^NX^N

Similarly, the question proceeds by telling us that: the woman's brother has the disease.

Definitely, it's possible that this unaffected woman is a carrier of the disease.

So, if she is a carrier; we have her traits to be: X^NX^n

NOW, if a cross exist between these couples; we have

X^NY     ×        X^NX^n

                     X^N                         Y

X^N                X^NX^N                  X^NY

X^n                 X^NX^n                   X^nY

So, we have offspring as follows:

X^NX^N  = normal unaffected female  

X^NY     = normal unaffected male

X^NX^n   = female carrier for the Duchenne muscular dystrophy disease

X^nY      = affected male with the Duchenne muscular dystrophy disease

So, the probability of the child to be affected with the disease = \frac{1}{4}

Also, the probability that the first child will be a male or a female = \frac{1}{2}

∴

the  probability that the couple’s first child will be affected = \frac{1}{4}*\frac{1}{2}

=\frac{1}{8}

4 0
3 years ago
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