<span>F- allele for freckles
f- </span><span>allele without freckles
1) The man is heterozygote and has freckles, its indicating that the allele for freckles is dominant.
A cross between him and a woman who is also </span><span>heterozygote: Ff x Ff
it would result in the following probabilities:
- 1/4 - homozygote with freckles: FF
- 2/4 - </span><span>heterozygote with freckles: Ff
- 1/4- </span><span>homozygote without freckles:ff
Their son would have a probability of 75% of being born with freckles.
2) The cross resulted in this probabilities:
</span><span><span>- 1/4 - homozygote with freckles: FF
- 2/4 - </span><span>heterozygote with freckles: Ff
- 1/4- </span><span>homozygote without freckles:ff
So, the chance of being born heterozygote for this gene is 2/4, which is the same as half (50%).
</span></span>
The answer is a <span>cat. </span>
I guess because of concentration.....it stops !
Answer:
No, glycolysis can not be continued without fermentation in the absence of oxygen.
Explanation:
In the absence of oxygen, cells perform fermentation to oxidize NADH into NAD+. NAD+ is required during the conversion of glyceraldehyde 3 phosphate into 1,3 bisphosphoglycerate. Fermentation reduces pyruvate and oxidizes NADH so that the NAD+ supply is continued to ensure continuity of glycolysis.
If fermentation does not occur under anaerobic conditions, cells will accumulate pyruvate and NADH. Glycolysis could not be continued in the absence of NAD+.
