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dusya [7]
2 years ago
8

2x + 72xx + 8x

Mathematics
1 answer:
valentinak56 [21]2 years ago
7 0

The area of the shaded region is 3x^2 + 6x

<h3>How to determine the area of the shaded region?</h3>

The given parameters are:

  • Top side of the shaded rectangle = 2x + 7.
  • Left side of the shaded rectangle = 2x.
  • Top side of the unshaded rectangle = x + 8.
  • Left side of the unshaded rectangle = x.

The area of the shaded region is calculated as:

Shaded region area = (Top side of the shaded rectangle * Left side of the shaded rectangle) - (Top side of the unshaded rectangle * Left side of the unshaded rectangle)

Substitute the known values in the above equation

Shaded region area = (2x + 7) * (2x) - (x + 8) * (x)

Evaluate the products

Shaded region area = (4x^2 + 14x) - (x^2 + 8x)

Open the bracket

Shaded region area = 4x^2 + 14x - x^2 - 8x

Collect the like terms

Shaded region area = 4x^2 - x^2 + 14x  - 8x

Evaluate the like terms

Shaded region area = 3x^2 + 6x

Hence, the area of the shaded region is 3x^2 + 6x

Read more about areas at:

brainly.com/question/25292087

#SPJ1

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ivanzaharov [21]
816.81
Hope this helps
4 0
3 years ago
An airplane moves at a constant speed of 120 miles per hour for 3 hours. How many miles does it go?
irina [24]

Answer:

120 miles per hour

total time 3 hours

120 x 3= 360

the plane travels 360 miles

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Consider the following problem: a farmer with 750 feet of fencing wants to enclose a rectangular area and then divide it into fo
nlexa [21]

Answer:

14,062.5ft^2

Step-by-step explanation:

A farmer has a given length of fencing. Since this fencing is used to enclose a rectangular area, before it is then divided it into four pens using the same provided fencing material. This will definitely lead to five lengths of fencing which come along one side of the rectangle to form four pens.

Let us assume that the length of the each of the five sides be xft.

Then let the length of each of the two sides in the be yft.

Since the total length of fencing available is 750 feet.

Then we can have an equation of such:

5x+2y=750

Making y the subject

2y = 750-5x

y = 750-5x/2. ........1

The area of the rectangular region is given by:

A = xy. ......... 2

Combining (1) in (2) to find the area

A(x)= x. (750−5x)/2

=750x−5x^2/2 ........... (*)

Going by the means of first diffential calculus.

A(x)=750x−5x^2/2

A'(x) = 750-10x/2

Setting A'(x) = 0

750-10x/2 = 0

750-10x = 2×0

750-10x = 0

750= 10x

x = 750/10

x = 75

Now that we have x = 75

We can now substitute into equation (*)

A(x) = 750×75-5×75^2/2

= (56250-28125)/2

= 28126/2

= 14062.5

Hence the rectangular region of maximum area is

14062.5ft^2

5 0
3 years ago
Find the slope passing through the points (-3,4) and (2,-1).
stellarik [79]
1)

Given two points: (x₁,y₁) and (x₂,y₂) the slope of the line passing through these points would be: 
m=(y₂-y₁)/(x₂-x₁)

Data:
We have two points, (-3,4) and (2,-1), therefore, the slope of the line passing through these points will be: 

m=(-1-4) /(2+3)=-5/5=-1

Answer: The slope would be -1. 

2)
slope-intercept form of a line:
y=mx+b
m=slope
b=y-intercept

Therefore:
m=2
b=y-intercept=-4

The line would be: y=2x-4

answer: the equation of this line would be: y=2x-4
3 0
3 years ago
Least common denominator (LCD) of 5/12 and 11/9
serious [3.7K]
Least common denominator is 36
5 0
3 years ago
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