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Naya [18.7K]
2 years ago
7

Given: PRbisects ZQPS, PQ = 12units, and PS= 12units

Mathematics
1 answer:
Ganezh [65]2 years ago
3 0

Answer:

Use SAS to show that triangles PRQ and PRS are congruent.

Step-by-step explanation:

Since PR bisects angle QPS, angles QPR and SPR are congruent. By reflexive property of congruence, PR is congruent to itself. Since PQ is congruent to PS, we can use SAS to show that the two triangles are congruent. By CPCTC, QR is congruent to SR.

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Use a transformation to solve the equation. w/4 = 8 can you also leave a detailed explanation on how this equation = 32
OverLord2011 [107]

Answer:

w=32

Step-by-step explanation:

w/4 = 8

4/1 * w/4 = 8*4

w=32

5 0
3 years ago
The width of a rectangle is 6 kilometers less than twice its length. if its area is 108 square​ kilometers, find the dimensions
Art [367]
Hi there!

Answer:
length = 9 kilometres
Width = 12 kilometres

Let's solve this problem step by step!
To find our answer we need to set up and solve an equation.

Let the length of the rectangle be represented by x.
The width of the rectangle can therefore be expressed by 2x - 6.

The area of a rectangle can be found by using the formula:
A = width × length

Plug in the data from the formula
A = x (2x - 6).

Simplify using rainbow technique.
x(2x - 6) = 2 {x}^{2} - 6x

Now we've found the simplified expression that expresses the area of the rectangle. Therefore, we can now set up and start solve the equation.

2 {x}^{2} - 6x = 108
Subtract 108

2 {x}^{2} - 6x - 108 = 0
Divide by 2.

{x}^{2} - 3x - 54
(x - 9)(x + 6) = 0
Rule AB = 0, gives A is 0 or B is 0.

x - 9 = 0 \\ x = 9 \\ \\ x + 6 = 0 \\ x = - 6

The length of the rectangle, which was represented by x, must be 9 (since it cannot be a negative number).

Length
x = 9
Width
2x - 6 = 2 \times 9- 6 = 18 - 6 = 12

Answer:
length = 9 kilometres
Width = 12 kilometres

~ Hope this helps you!
6 0
3 years ago
Multiply the trinomial x^2+xy+y^2 times the binomial x-y and simplify.
Natalija [7]
Multiply then simplify, that's doing the same work twice...anyway

x^3+x^2y+xy^2-x^2y-xy^2-y^3

x^3-y^3  which if factored is:

(x-y)(x^2+xy+y^2)  which is what you started with :)
6 0
3 years ago
Which point satisfies the inquality 2×+y > 10 a. (2,3) b.(3,4) c. (3,2) d. (4,3)
Anna11 [10]
D. (4,3) that's the answer
8 0
4 years ago
What’s the answer please help !!!!
baherus [9]
I think the answer is x>-3
5 0
3 years ago
Read 2 more answers
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