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Neporo4naja [7]
3 years ago
14

How many hundredths in 4.97

Mathematics
2 answers:
Oksanka [162]3 years ago
7 0
7 is in the hundredths place.
There are 7 one hundredths.
monitta3 years ago
7 0
7 hundredths is the answer. .9 is tenths position and the 7 is in the hundredths position.
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denis23 [38]
In centre is the centre of a circle that is inscribed in a triangle, called the incircle, i.e. circle is tangent to all three sides AND located inside the triangle.  An incircle is roughly sketched in the accompanying diagram.

Since all radii of an incircle are equal, we have
4x-1=6x-5
Solving for x,
6x-4x=5-1
x=2
consequently, distance from incentre to each side of the triangle is
4(2)-1=7
check 6x-5=6(2)-5=7... checks.

Answers:
The value of x = 2
The distance from incentre to side of triangle is 7
5 0
3 years ago
Can someone help will name brainliest if the answer is correct
Neporo4naja [7]

Answer:

64 hope it helps

Step-by-step explanation:

6 0
3 years ago
Marisol has enough tile to cover a square portion of her patio with an area of 225 ft2. What will be the side lengths of her des
Anit [1.1K]

Answer:

Side lengths = 15 ft²

Step-by-step explanation:

Given:

Area of square = 255 ft²

Find:

Side lengths

Computation:

Area of square = side x side

Area of square = 255 ft²

Side lengths = √Area of square

Side lengths = √255

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4 0
3 years ago
Reversing coins there are n coins, each showing either heads or tails. we would like all the coins to show the same face. what i
Katarina [22]
If there are n coins, then the smallest (minimum) amount of coins we need to flip is 1. The reason why is because the best case scenario would be flipping all heads except the last coin which is tails. This scenario is rare if n is large, but still possible.
8 0
3 years ago
sheldon bought 4 1/2 kg of plant food. he uses 1 2/3 kg on his strawberry plant and used 1/4 kg for his tomato plant. how many k
fenix001 [56]

Answer:

Sheldon have left 2\frac{7}{12}\ kg of food.

Step-by-step explanation:

Quantity of food = 4\frac{1}{2}=\frac{9}{2} kg

Quantity used on strawberry plant = 1\frac{2}{3} = \frac{5}{3}\ kg

Quantity used on tomato plant = \frac{1}{4}\ kg

Food left = Total - used on strawberry - used on tomato

Food left = \frac{9}{2}-\frac{5}{3}-\frac{1}{4}

Food left = \frac{54-20-3}{12} = \frac{31}{12}

Food left = 2\frac{7}{12}\ kg

Therefore,

Sheldon have left 2\frac{7}{12}\ kg of food.

4 0
3 years ago
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