Ahh this is a good hard question hopefully someone comes along and helps you out with it. Goodluck my friend!
Answer:
59.2 m
Step-by-step explanation:
The tangent of the angle of elevation will be the ratio of pole height to distance from the pole:
tan(2α) = h/10
tan(α) = h/70
The double-angle formula for tangents tells us ...
tan(2α) = 2tan(α)/(1 -tan(α)²)
Multiplying by the denominator and substituting from above, we get ...
(1 -(h/70)²)(h/10) = 2(h/70)
7(1 -(h/70)²) = 2 . . . . . . . . multiply by 70/h
1 - 2/7 = (h/70)² . . . . . . . . divide by 7, subtract 2/7-(h/70)²; next: square root
h = 70√(5/7) ≈ 59.2 . . . . meters
The height of the top of the pole is about 59.2 meters above the observer.
Step 1: Subtract -2 from both sides.<span><span><span><span>
m2</span>+<span>4m</span></span>−<span>(<span>−2</span>)</span></span>=<span><span>−2</span>−<span>(<span>−2</span>)</span></span></span><span><span><span><span>
m2</span>+<span>4m</span></span>+2</span>=0</span>
Step 2: Use quadratic formula with a=1, b=4, c=2.<span>
m=<span><span><span>−b</span>±<span>√<span><span>b2</span>−<span><span>4a</span>c</span></span></span></span><span>2a</span></span></span><span>
m=<span><span><span>−<span>(4)</span></span>±<span>√<span><span><span>(4)</span>2</span>−<span><span>4<span>(1)</span></span><span>(2)</span></span></span></span></span><span>2<span>(1)</span></span></span></span><span>
m=<span><span><span>−4</span>±<span>√8</span></span>2</span></span><span><span>
m=<span><span>−2</span>+<span><span><span>√2</span><span> or </span></span>m</span></span></span>=<span><span>−2</span>−<span>√2</span></span></span><span>
</span>
Answer:
18
Step-by-step explanation: