The answer is 2/5
-1/5 + 3/5
(-1) + 3
————
5
=2/5
Answer:
13 + 5x
Step-by-step explanation:
Step 1:
9 + 4 + x + 4x
Step 2:
13 + x + 4x
Answer:
13 + 5x
Hope This Helps :)
Answer:
Population in 2013 is 132.76 ≈ 133 million.
Step-by-step explanation:
A country's population in 1990 was 123 million
In 2002 it was 128 million.
We have to calculate the population in 2013.
Since population growth is always represented by exponential function.
It is represented by
Here t is time in years, k is the growth constant, and is initial population.
For year 1990 ⇒
128 = =
taking ln on both the sides ⇒
ln
ln 128 - ln 123 = 12k [since ln e = 1 ]
4.852 - 4.81218 = 12 k
k =
For year 2013 ⇒
= 123 ×
= 123 × 1.07937
= 132.76 rounded to 133 million.
Therefore, population in 2013 is 132.76 ≈ 133 million.
Step-by-step explanation:
In order to graph this system of equations, you have to put the equations in terms of y so that you can graph it by hand.
For the first equation:
Subtract x on both sides so that it reads to be
For the second equation:
Subtract 3x on both sides and divide by -1 to make the y positive. Remember that when you divide, the sign always flips:
So the two equations you have to graph now are and .
In order to graph, start from your y-intercept for each of the equations and go vertical/horizontal based on the coefficient of your equation. For instance, for your first equation, you would go down -1 and to the right 1. Repeat until your whole equation is graphed. For the second equation your coefficient is 3, so you would go up 3 from -4 and to the right 1. Repeat.
Once you have your equations graphed, you need to find where the two graphs both have solutions. To do this, pick any point from the graph and plug it into the x and y of one equation. If the equation equals itself, then that area is the solution of the graph for that equation. Make sure to do this for both equations. Once you find the area in which both equations have solutions for each other, that is the area that needs to be shaded.
Here is what your graph should look like: