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2 years ago

Please help me solve this.

Mathematics

2 answers:

san4es73 [151]2 years ago

4 0

the answer is x is equals to 2 or x is equal to -5 in the equation x square + 3x - 10 is equals to zero where after solving you get x square + 5 x - 2 x - 10 is equals to zero you factorise you get x (x + 5) - 2 (x + 5) is equal to zero then after solving x is equals to 2 or -5

Vladimir79 [104]2 years ago

3 0

-x=2 that is the answer

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3 years ago

Need help on these, thank you!

tensa zangetsu [6.8K]

Answer:

$5x+2 , 2x^2+5x-2,\frac{x^2+5x}{2-x^2}$

Step-by-step explanation:

We are given f(x) and g(x)

1. (f+g)(x)

(f+g)(x) = f(x) + g(x)

= $x^2+5x+2-x^2$

= $5x+2$

Domain : All real numbers as it there exists a value of (f+g)(x) f every x .

2. (f-g)(x)

(f-g)(x) = f(x)-g(x)

= $x^2+5x-2+x^2$

= $2x^2+5x-2$

Domain : All real numbers as it there exists a value of (f-g)(x) f every x .

Part 3 .

$(\frac{f}{g})(x)\\(\frac{f}{g})(x) = \frac{f(x)}{g(x)}\\=\frac{x^2+5x}{2-x^2}$

Domain : In this case we see that the function is not defined for values of x for which the denominator becomes 0 or less than zero . Hence only those values of x are defined for which

$2-x^2>0$