<span>Part A
</span>f(x)=30∗0.2xand<span>f(x)=45+3x</span><span>
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Part B</span>
f(x)=30+0.2(5)f(x)=45+3(5)<span>
Neighborhood A and neighborhood B both have 60 houses after 5 years
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Part C
1 year
A=36
B=48
2 years
A=42
B=51
3 years
A=48
B=54
4 years
A = 54
B = 57
5 years
A = 60
B= 60
Step-by-step explanation:
Hey, there!
Here,
Given that:

we need to find factor,
As it is in a^2-b^2 form as per its factor (a+b) (a-b), keeping same formula here,
25x^2 means (5x)^2
and 4 means 2^2
Now, it would be,


Therefore, it's factor would be (5x+2)(5x-2).
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
The answer is 5x-89 Hope I helped!
Solution :
It is given that a large institution is preparing food menus which contains foods A as well as B.
Each lunch provides :
10 units of carbohydrates
6 units of fats
7 units of proteins
The food from A cost = $0.12 per ounce
And food from B cost = $0.08 per ounce
Objective function :

Constraints : 
Domain : 
Range :
Answer:
C
Step-by-step explanation:
pythagorean theorem: a²+b² = c²
area of square = length²
c = side opposite right angle = length of square Z
thus, area of square Z = c²
area of square X = a² (or b², it doesn't matter)
area of square Y = b² (or a²)
a² + b² = c²
region x + region y = region z