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2 years ago

What is the slope-intercept equation for this line?

Mathematics

1 answer:

Vaselesa [24]2 years ago

3 0

Answer:

$y=-\frac{1}{4} x-1$

Step-by-step explanation:

find the slope of the line using the two points (0,-1) and (4,-2)

$\frac{(-2+1)}{(4-0)} =-\frac{1}{4}$

since we already know that the y-intercept is -1 then you plug the numbers into the slope-intercept form y=mx+b and you get $y=-\frac{1}{4}x-1$

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If f(x)=7x+4x and g(x) =1/2x what is the value of (f/g)(5)

Aliun [14]

Answer:

(f/g)(5) = 22

Step-by-step explanation:

All we need to do is plug in 5 for x in both f(x) and g(x) then divide the result of f(x) and g(x) to find our final answer.

Step 1: Plug in 5 for x

f(x) = 7(5) + 4(5) = 55

g(x) = 1/2(5) = 2.5

Step 2: Divide f(x) by g(x)

f(5)/g(5) = 55/2.5 = 22

And we have our final answer!

4 0

3 years ago

1/2 of the people in the clinic are men, 1/3 are elderly, how many people are not elderly or men?

Nostrana [21]

1/6 of the people are not elderly or men

<h3>How to determine the proportion?</h3>

The given parameters are:

Men = 1/2

Elderly = 1/3

The number of people that are not elderly or men are:

People = 1 - Men - Elderly

So, we have:

People = 1 - 1/2 - 1/3

Evaluate

People = 1/6

Hence, 1/6 of the people are not elderly or men

Read more about proportion at:

brainly.com/question/1781657

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2 years ago

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skelet666 [1.2K]

Answer:

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Step-by-step explanation:

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3 years ago

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How do u do this step by step ? -8 ÷ 3.2

Ad libitum [116K]

Answer:

the answer is -2.5

Step-by-step explanation:

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2 years ago

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the half-life of strontium-90 is approximately 29 years. how much of a 500 g sample of strontium-90 will remain after 58 years

Yuliya22 [10]

Answer: 125 g

<u>Step-by-step explanation:</u>

$A = P_o\cdot e^{kt}\\\\\text{First, use the given information to find k:}\\\\\bullet A=\dfrac{1}{2}P_o\\\\\bullet k = unknown\\\\\bullet t=29\text{ years}\\\\\dfrac{1}{2}P_o=P_o\cdot e^{k(29)}\\\\\\\dfrac{1}{2}=e^{k(29)}\qquad divided\ both\ sides\ by\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=ln\bigg(e^{k(29)}\bigg)\qquad applied\ ln\ to\ both\ sides\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=29k\qquad simplified-ln\ and\ e\ cancel\ out\\\\\\\dfrac{ln\bigg(\dfrac{1}{2}\bigg)}{29}=k\qquad divided\ 29\ from\ both\ sides\\\\\\-0.0239=k$

$\text{Now, use the following in the equation to solve for A:}\\\\\bullet A=unknown\\\bullet P_o=500\\\bullet k=-0.0239\\\bullet t=58\text{ years}\\\\A=500\cdot e^{(-0.0239)(58)}\\\\.\quad=500\cdot e^{-1.386}\\\\.\quad=125$

8 0

4 years ago