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bogdanovich [222]
2 years ago
7

A lawn with an area of 300 square feet needs 1/2 pound of grass seed. How many pounds of grass seed are needed for a lawn that i

s 60 feet long and 20 feet wide?
Please show the math.
Mathematics
1 answer:
lana66690 [7]2 years ago
4 0
2 pounds.

60(20) = 1200 = area
If 300 square feet requires 1/2 pound, you can divide 1200 square feet by 300 square feet.

1200/300=4
4 times 1/2
4(1/2)=2

For every 300 square feet, you need half a pound. If you were to have 600 square feet, you would need a pound of grass seed. Therefore, for 1200 square feet, you need 2 pounds of grass seed.
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The input it taken as the unknown base value, while the output here is the area of the trapezoid. b is therefore the base value, and A( b ) is the area of the trapezoid. Let's formulate the equation for the area of the trapezoid, and isolate the area of the trapezoid. To find the inverse of this function, switch y ( this is A( b ) ) and b, solving for y once more, y ➡ y ⁻ ¹.

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