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bogdanovich [222]
3 years ago
7

A lawn with an area of 300 square feet needs 1/2 pound of grass seed. How many pounds of grass seed are needed for a lawn that i

s 60 feet long and 20 feet wide?
Please show the math.
Mathematics
1 answer:
lana66690 [7]3 years ago
4 0
2 pounds.

60(20) = 1200 = area
If 300 square feet requires 1/2 pound, you can divide 1200 square feet by 300 square feet.

1200/300=4
4 times 1/2
4(1/2)=2

For every 300 square feet, you need half a pound. If you were to have 600 square feet, you would need a pound of grass seed. Therefore, for 1200 square feet, you need 2 pounds of grass seed.
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Answer:

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Step-by-step explanation:

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Answer:

See picture.

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Step-by-step explanation:

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3 years ago
Solve the following equation simultaneously 1/x-5/y=7, 2/x+1/y=3​
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Answer:

  (x, y) = (1/2, -1)

Step-by-step explanation:

Subtracting twice the first equation from the second gives ...

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Using the second equation, we can find x:

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The solution is (x, y) = (1/2, -1).

_____

<em>Additional comment</em>

If you clear fractions by multiplying each equation by xy, the problem becomes one of solving simultaneous 2nd-degree equations. It is much easier to consider this a system of linear equations, where the variable is 1/x or 1/y. Solving for the values of those gives you the values of x and y.

A graph of the original equations gives you an extraneous solution of (x, y) = (0, 0) along with the real solution (x, y) = (0.5, -1).

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2 years ago
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3 years ago
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