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bogdanovich [222]
3 years ago
7

A lawn with an area of 300 square feet needs 1/2 pound of grass seed. How many pounds of grass seed are needed for a lawn that i

s 60 feet long and 20 feet wide?
Please show the math.
Mathematics
1 answer:
lana66690 [7]3 years ago
4 0
2 pounds.

60(20) = 1200 = area
If 300 square feet requires 1/2 pound, you can divide 1200 square feet by 300 square feet.

1200/300=4
4 times 1/2
4(1/2)=2

For every 300 square feet, you need half a pound. If you were to have 600 square feet, you would need a pound of grass seed. Therefore, for 1200 square feet, you need 2 pounds of grass seed.
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The correct  option (D).

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<h3>What is liner equation?</h3>

a two-variable equation that, when plotted on a graph, results in a straight line.

<h3>What does intersection point mean?</h3>

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<h3>According to the given information:</h3>

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I understand that the question you are looking for is:

Russ is solving an equation where both sides are linear expressions. He sets the expressions equal to y and graphs the system finding that they are the same line. How should Russ interpret this outcome? There are no intersection points. There is exactly one intersection point. There are exactly two intersection points. There are infinitely many intersection points.Russ is solving an equation where both sides are linear expressions. He sets the expressions equal to y and graphs the system finding that they are the same line. How should Russ interpret this outcome?

A. There are no intersection points.

B. There is exactly one intersection point.

C. There are exactly two intersection points.

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