Assume w is the width. the length is 3*2w
To fence the whole outside of farm, he needs:
2(w+6w)=14w meters
Also he needs one width and one length for the enclosed pens. Therefore, the total amount of fencing he would need:
14w+w+6w=21w meters
The least common multiple is 60
Answer:
≈150.8
Step-by-step explanation:
The equation for a cylinders surface area ia 2×π×r×h+2×π×r²
Or you can go on google and type in "cylinder surface area"
Answer is B.
We see the center lines are 80 and 85 as stated.
A is wrong because the range of class 2 is less.
C is wrong; class 2 has a minimum of 50
D is wrong; class 2 has a smaller interquartile range, which is the width of the boxes.
