Determine the period of this function

Mathematics

1 answer:

Salsk061 [2.6K]3 years ago

5 0

<h3>Answer: C) 6</h3>

Explanation:

The function is somewhat sinusoidal but not entirely. Its composed of piecewise line segments when we should have a single continuous smooth curve; however, it's still periodic since it repeats itself.

Let's start at the top at the left most corner. This point has x coordinate of x = 1.

The other endpoint of this top left flat portion is when x = 2. Then the function curve goes downhill until it reaches x = 4. From x = 4 to x = 5, we're at the flat bottom part. From x = 5 to x = 7 is when the function increases.

Once we get to x = 7, the process described earlier starts all over again. So this is when the cycle ends and the length of the period is 7-1 = 6 units. The function repeats itself every 6 units, or you can say the length of each cycle is 6 time units (eg: 6 seconds).

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Full steps and all reasons, thanks!

Nataly_w [17]

You can focus on the two sub-triangles ABC and ACD

We know that they are both right triangles, because we're given that AC and BD are perpendicular.

The sides AB and AD are the hypothenuses of these triangles, so we know their length through the pythagorean theorem:

$AD^2 = AC^2+CD^2$

$AB^2 = AC^2+BC^2$

But since we're given $BC=CD$ , the expressions for AD and AB are actually the same expression. This proves that AD=AB, and thus that the triangle is isosceles.