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Burka [1]
2 years ago
11

Rectangle STUV is shown on a coordinate plane. Rectangle STUV with vertices S at negative 7 comma 6, T at negative 2 comma 6, U

at negative 2 comma 1, and V at negative 7 comma 1. If rectangle STUV is translated using the rule (x, y) → (x − 2, y − 4) and then rotated 90° counterclockwise, what is the location of T″? (3, −9) (3, −4) (−2, −4) (−2, −9)
Mathematics
2 answers:
rusak2 [61]2 years ago
4 0

The coordinate of the point T after the given transformations is; T''(-2, -4)

<h3>How to carry out Translation Transformations?</h3>

We are given the coordinates of the rectangle STUV as;

S(-7, 6)

T(-2, 6)

U(-2, 1)

V(-7, 1)

Now, we are told that all these coordinates are translated using the transformation rule;  (x, y) → (x − 2, y − 4)

Thus, the new coordinates using this transformation rule are;

S'(-9, 2)

T'(-4, 2)

U'(-4, -3)

V'(-9, -3)

Now, we are told that these new points are  rotated 90° counterclockwise and as such the new coordinates formed will follow the pattern (x, y) → (-y, x).

Thus, our final coordinates are;

S''(-2, -9)

T''(-2, -4)

U''(3, -4)

V''(3, -9)

Thus, the coordinate of the point T after the given transformations is; T''(-2, -4)

Read more about Translation Transformation at; brainly.com/question/4289712

#SPJ1

Vitek1552 [10]2 years ago
4 0

Answer:

(−2, −4)

Step-by-step explanation:

The other person is correct, thank you, and this is support to the answer.

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4 0
2 years ago
Read 2 more answers
a rectangular prism has a volume of 1374.28 cubic inches.The prism is 9.4 inches wide and 17.2 inches long.What is the height of
NISA [10]
The volume V of a prism can be found by:
The volume of a rectangular prism can be found through:
V=lwh
Where l is the length, w is the width, and h is the height.

The height can be found by rearranging the equation to:
h= \frac{V}{wl}

Take the volume (1374.28) and divide it by the length times the width (9.4*17.2=161.68).
1374.28/161.68= 8.5 inches is the height of the prism.
6 0
3 years ago
A ship travels 62.5 km in 1st hour of sailing. Starting from 2nd hour, the distance travelled per hour is x% of that in the prec
Bas_tet [7]
Speed of the ship in the second hour =  (62.5 * x ) / 100  kph.

In third hour it is  [(62 * x) / 100 ] * x/100]

is 4th hour its is the above * x/100 again  so we can now form the equation

62.5x      x          x
------- *   ----  *  ----    =  32
100      100      100

62,5 x^3 = 32,000,000
x^3 =  512,000
x = 80 <-----  Answer  to (a)

(b)  Ship travels 62.5 in first hour then  this falls by a common ratio of 0.8 each hour so we have a geometric sequence 

Dist travelled in 6 hours  =  a1  1 - r^n
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                                               1 - r

Answer is    230.56 km 




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Answer:

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Step-by-step explanation:

4 0
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cestrela7 [59]

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