Answer:
Domain of y=![\sqrt[4]{x-1}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx-1%7D)
: is x>=1
Interval notation: [1,∞)
Step-by-step explanation:
We have y=
1) The domain of a function is the set of x values for which the function is real and defined.
2) So, x-1 should be positive means x-1>=0, because fourth root of any negative value would be a complex number and not a real number.
3) Now we solve the inequality x-1>=0
4) Adding 1 to both sides of the inequality we get,
x-1+1 > = 0+1
5) Cancel out -1 and +1 from the left side
6) We get x>=1
It concludes that for the domain of the given function, the x value must be greater than or equal to 1
Answer: 7
Step-by-step explanation: You first distribute 3, and -2. This gets you 7 = 3t -3 -2t +3. Then you add like terms which gets you, 7 = t.
Let x and y represent the two numbers that add up to 24.
x + y = 24
=> y = 24 - x
The product of the two numbers is P = x*y = x*(24 - x) = 24x - x^2.
To maximize the product P, solve P' = 0 for x.
P' = 24 - 2x
24 - 2x = 0
=> x = 12
Also P'' = -2 which is negative
for x = 12
The product when x = 12 is 12*12 = 144
hope it helps!
Hello!
We solve this algebraically
y + 6 = 3/2(x - 4)
We distribute the 3/2
y + 6 = 3/2x - 6
If you work with decimals easier we can make 3/2 into a decimal
y + 6 = 1.5x - 6
Add 6 to both sides
y + 12 = 1.5x
subtract y from both sides
1.5x + -y = 12
Hope this helps!
Answer:
32
Step-by-step explanation:
I did the math for you
