The four numbers are: -4, -2 ,0, 2 Answer.
How do you solve this: the sum of four consecutive even integers is equal to least of the integer
Solution: Let the numbers be n, n+2, n+4 and n+6.
Their sum = 4n+12 = n or
3n+12 = , or
3n = -12,
n= -4
therefore we get -4, -2, 0, 2
The four numbers are: -4, -2 ,0, 2 . Answer.
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