Answer:
Step-by-step explanation:
1. not equivalent
2. not equivalent
3. fully simplified
4.not fully simplified
5. not fully simplified
6. not fully simplified
Piecewise Function is like multiple functions with a speific/given domain in one set, or three in one for easier understanding, perhaps.
To evaluate the function, we have to check which value to evalue and which domain is fit or perfect for the three functions.
Since we want to evaluate x = -8 and x = 4. That means x^2 cannot be used because the given domain is less than -8 and 4. For the cube root of x, the domain is given from -8 to 1. That meand we can substitute x = -8 in the cube root function because the cube root contains -8 in domain but can't substitute x = 4 in since it doesn't contain 4 in domain.
Last is the constant function where x ≥ 1. We can substitute x = 4 because it is contained in domain.
Therefore:
![\large{ \begin{cases} f( - 8 ) = \sqrt[3]{ - 8} \\ f(4) = 3 \end{cases}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%20%5Cbegin%7Bcases%7D%20f%28%20-%208%20%29%20%3D%20%20%20%5Csqrt%5B3%5D%7B%20-%208%7D%20%20%5C%5C%20f%284%29%20%3D%203%20%5Cend%7Bcases%7D%7D)
The nth root of a can contain negative number only if n is an odd number.
![\large{ \begin{cases} f( - 8 ) = \sqrt[3]{ - 2 \times - 2 \times - 2} \\ f(4) = 3 \end{cases}} \\ \large{ \begin{cases} f( - 8 ) = - 2\\ f(4) = 3 \end{cases}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%20%5Cbegin%7Bcases%7D%20f%28%20-%208%20%29%20%3D%20%20%20%5Csqrt%5B3%5D%7B%20-%202%20%5Ctimes%20-%20%202%20%5Ctimes%20%20%20-%202%7D%20%20%5C%5C%20f%284%29%20%3D%203%20%5Cend%7Bcases%7D%7D%20%5C%5C%20%20%5Clarge%7B%20%20%5Cbegin%7Bcases%7D%20f%28%20-%208%20%29%20%3D%20%20-%202%5C%5C%20f%284%29%20%3D%203%20%5Cend%7Bcases%7D%7D)
Answer
1.
height= 3
length= 5
width= 4
The number of cubes would be the result of the multiplication of the side measures. Doing so, we have:
3 x 5 x 4 = 60
We need 60 blocks
2
height= 4
length= 6
width= 4
The number of cubes would be the result of the multiplication of the side measures. Doing so, we have:
4 x 6 x 4 = 96
We need 96 blocks
3
height= 2
length= 3
width= 4
The number of cubes would be the result of the multiplication of the side measures. Doing so, we have:
2 x 3 x 4 = 24
We need 24 blocks
4
height= 4
length= 8
width= 6
The number of cubes would be the result of the multiplication of the side measures. Doing so, we have:
4 x 8 x 6 = 192
We need 192 blocks
5
height= 2
length= 6
width= 4
The number of cubes would be the result of the multiplication of the side measures. Doing so, we have:
2 x 6 x 4 = 48
We need 48 blocks
6
height= 1
length= 5
width= 3
The number of cubes would be the result of the multiplication of the side measures. Doing so, we have:
1 x 5 x 3 = 15
We need 15 blocks
7
Answer:
<em>Option A, Option C, Option E</em>
Step-by-step explanation:
The area of a kite can be identified through 1 / 2 of the multiplication of each diagonal. The first diagonal is equivalent to the addition of 50 cm and 10 cm, while the second is of length 20 cm + 20 cm.

Consider the first option. If we take a look at the bit 2 * ( 1 / 2 * 20 * 50 ) the 2 and 1 /2 cancel each other out, leaving you with 20 * 50 = 1000 . Respectively in the expression 2 * ( 1 / 2 * 20 * 10 ) the 2 and 1 / 2 cancel each other out, leaving you with 20 * 10 = 200;

The second option considers the expression 2 * ( 1 / 2 * 20 * 60 ). Again, the 2 and 1 / 2 cancel each other out, leaving you with 20 * 60;

Option C is a similar version of option a, besides the fact that the 1 / 2 doesn't exist. Thus, Option C is incorrect!
Option D is a similar version of option a as well, but as the 2 doesn't exist, it is incorrect!
This last option, option E is taken as 1 / 2 of the multiplication of the diagonals, and thus is correct!
