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2 years ago

Given negative four and one sixth times negative three and fifteen hundredths, determine the product.

Mathematics

1 answer:

Contact [7]2 years ago

3 0

The sum of the digits, B. thirteen and one eighth, is the product of the numerals.

<h3>How do you compute the value of the product?</h3>

According to the data, we are in the negative four hundred and one-sixth times the negative three hundred and fifteen-hundredths range.

This is going to be the product:

= (-4 1/6) × (-3 15/)

= - 4 1/6 × 3 3/20

= - 25/6 × -63/20

x= 13 1/8

In conclusion, The answer that you should choose is an option (d), which is thirteen and one-eighth.

Find out more about the product by visiting:

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To answer this question, multiply all given numbers together.

4*3*3

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3 years ago

A taxi charges a flat rate of $1.75, plus an additional $0.65 per mile. If Erica has at most $10.20 to spend on a

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3 years ago

Solve sin 0 + 1 = cos20 on the interval 0 ≤ 0 < 2pi. Show work please!

yan [13]

Answer:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}\frac{2\pi}{3}\frac{4\pi}{3}$

Step-by-step explanation:

You need 2 things in order to solve this equation: a trig identity sheet and a unit circle.

You will find when you look on your trig identity sheet that

$cos(2\theta)=1-2sin^2(\theta)$

so we will make that replacement, getting everything in terms of sin:

$sin(\theta)+1=1-2sin^2(\theta)$

Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:

$2sin^2(\theta)+sin(\theta)=0$

We can factor out the sin(theta), since it's common in both terms:

$sin(\theta)(2sin(\theta)+1)=0$

Because of the Zero Product Property, either

$sin(\theta)=0$ or

$2sin(\theta)+1=0$

Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi. They are:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}$

The next equation needs to first be solved for sin(theta):

$2sin(\theta)+1=0$ so

$2sin(\theta)=-1$ and

$sin(\theta)=-\frac{1}{2}$

Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval. They are:

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3 years ago

My friend sets out walking at a speed of $3$ miles per hour. I set out behind her $5$ minutes later at $4$ miles per hour. When

r-ruslan [8.4K]

Answer: The answer is 0.25 miles.

Step-by-step explanation: Given that my friend started walking at a speed of 3 miles per hour and I started 5 minutes after him at a speed of 4 miles per hour. We need to find the number of miles my friend travelled when I started walking.

Since I started 5 minutes after than my friend, so we are to find the distance travelled by my friend in 5 minutes.

In 1 hour, i.e., 60 minutes, distance travelled by my friend = 3 miles.

In 1 minute, distance travelled by my friend is

$\dfrac{3}{60}=\dfrac{1}{20}~\textup{miles}.$

Therefore, distance travelled by my friend in 5 minutes will be

$\dfrac{1}{20}\times 5=\dfrac{1}{4}=0.25~\textup{miles}.$

Thus, the answer is 0.25 miles.

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3 years ago

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