2 years ago

a triangle has two sides of length 6 and 1. What is the smallest possible whole-number length for the third side?

1 answer:

7 0

You’d have to use the Pythagorean Thereom. a^2 + b^2 = c^2. then figure out the smallest side length from there

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timurjin [86]

1% is the answer because you have to bump it up two place and it is always the first number.

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lubasha [3.4K]

Answer:

For the second one: NO congruent to MO.

For the third one: angle N congruent to angle O.

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Bezzdna [24]

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$\frac{2}{3} \div ( - \frac{9}{4} ) = \\$

$\frac{2}{3} \times( - \frac{4}{9}) = \\$

$- \frac{2 \times 4}{3 \times 9} = - \frac{8}{27} = - ({ \frac{2}{3} })^{3} \\$

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2 years ago

dimulka [17.4K]

The answer to the problem is 6,-6

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2 years ago

Jet001 [13]

Answer:

x = 7

Step-by-step explanation:

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2 years ago