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fredd [130]
2 years ago
10

at one of george washington's parties, each man shook hands with everyone except his spouse, and no handshakes took place betwee

n women. if 1313 married couples attended, how many handshakes were there among these 2626 people?
Mathematics
1 answer:
Keith_Richards [23]2 years ago
7 0

The total number of handshakes was 234.

  • The first man shook hands with 12 other men.
  • The second man shakes hands with 11 other men, as he had already shaken hands with the first man.
  • Like-wise, the last man does not need to shake hands again as every man has already shaken hands with him in their respective turns.
  • The number of handshakes among men is 0 + 1 + 2 + … + 12.
  • The sum of "n" natural numbers = (n)(n+1)/2
  • The number of handshakes among men is 12(13)/2.
  • The number of handshakes among men is 78.
  • Each man shakes hands with every woman except his spouse.
  • Each man shakes hands with 12 other women.
  • The number of handshakes between men and women is 13*12.
  • The number of handshakes between men and women is 156.
  • The total number of handshakes is 78 + 156.
  • The total number of handshakes is 234.

To learn more about natural numbers, visit :

brainly.com/question/17429689

#SPJ4

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