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VikaD [51]
3 years ago
7

Describe the relationship between the area of a circle and its circumstances

Mathematics
1 answer:
valentina_108 [34]3 years ago
6 0

Answer:

A = \frac{r}{2}C

Step-by-step explanation:

Given

Shape: Circle

Required

The area and the circumference (relationship)

This implies that, we write an expression that relates the area and the circumference.

Circumference is calculated as:

C = 2\pi r

Area is calculated as:

A = \pi r^2

The area can be rewritten as:

A = \frac{2\pi r^2}{2}

Further rewrite as:

A = \frac{r}{2}*2\pi r

Recall that:C = 2\pi r

So, the expression becomes

A = \frac{r}{2}*C

A = \frac{r}{2}C

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Use the equation
For A. The problem would be set up like so

5 _ -1
--------
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5 0
3 years ago
Given: QR I PT and ZQPR = ZSTR
Rina8888 [55]

Answer:

\triangle PQR \sim \triangle TSR

Step-by-step explanation:

Given :

QR⊥PT

\angle QPR = \angle STR

To Prove : \triangle PQR \sim \triangle TSR

Solution:

Statements                                            Reasons

QR⊥PT                                                Given

∠QRP and ∠SRT are right angles       Def of perpendicular

∠QPR≅∠STR                                     Given

∠QRP = ∠SRT                                    All right angles are equal

ΔPQR≈ΔTSR                                     AA similarity

Hence  \triangle PQR \sim \triangle TSR

5 0
4 years ago
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